Question

4x^2-28x-72 factor this please

Answer 1

Answer:

$4*(x-9)*(x+2)$

Step-by-step explanation:

Start by extracting the numerical common factors. Notice that 4 is a factor in all coefficients. Therefore: $4x^2-28x-72=4(x^2-7x-18)$

Now study the trinomial that is left, and look for numerical coefficients that multiplied give as result the last coefficient in the trinomial (-18) and when combined give you the coefficient in the linear term (-7). Notice that the coefficient -18 can be created by the product of (-9) times (2), and that these numbers combined give you exactly "-7" which is your middle coefficient. Therefore use them to factor out the trinomial:

$x^2-7x-18=x^2-9x+2x-18=\\=x^2-9x+2(x-9)=x(x-9)+2(x-9)=\\=(x-9)*(x+2)$

Therefore, the full factoring of the initial trinomial is written as: $4*(x-9)*(x+2)$

Answer 2

Answe45

Step-by-step explanation: