Answer:
The formatting on this is a little weird but if I'm reading it correctly:
1) 3.38
2) 7.29
3) 0.05
4) 0.42
Answer:
see below:
Step-by-step explanation:
2y–6=0
a. slope intercept form using y = mx + b
y = 6/2
y = 3
b. slope: use the slope intercept form: y = mx + b
slope = m = 0
c. y-intercept = (0,3)
The measure of the angle FEG is probably the same as the measure of the angle FDG. There is nothing saying that EF is parallel to DG, but if so, the measure of the angle FEG is also 50º.
When the diagonals of a trapezium with two parallel bases inside of a circle are drawn, they make the same angle measure with those bases.
Let us take 'a' in the place of 'y' so the equation becomes
(y+x) (ax+b)
Step-by-step explanation:
<u>Step 1:</u>
(a + x) (ax + b)
<u>Step 2: Proof</u>
Checking polynomial identity.
(ax+b )(x+a) = FOIL
(ax+b)(x+a)
ax^2+a^2x is the First Term in the FOIL
ax^2 + a^2x + bx + ab
(ax+b)(x+a)+bx+ab is the Second Term in the FOIL
Add both expressions together from First and Second Term
= ax^2 + a^2x + bx + ab
<u>Step 3: Proof
</u>
(ax+b)(x+a) = ax^2 + a^2x + bx + ab
Identity is Found
.
Trying with numbers now
(ax+b)(x+a) = ax^2 + a^2x + bx + ab
((2*5)+8)(5+2) =(2*5^2)+(2^2*5)+(8*5)+(2*8)
((10)+8)(7) =(2*25)+(4*5)+(40)+(16)
(18)(7) =(50)+(20)+(56)
126 =126
<u>Given</u>:
The given expression is 
We need to determine the values for which the domain is restricted.
<u>Restricted values:</u>
Let us determine the values restricted from the domain.
To determine the restricted values from the domain, let us set the denominator the function not equal to zero.
Thus, we have;
Taking square root on both sides, we get;
Thus, the restricted value from the domain is
Hence, Option A is the correct answer.
