From the periodic table you get the atomic masses of each element.
These are the values that I have in my periodic table (use those numbers of your periodic table if your teache gave you a specific one)
Na: 23 g/mol
O: 16 g/mol
H: 1 g/mol
C: 12 g/mol
Ca: 40 g/mol
S: 32 g/mol
Mg: 24 g/mol
P: 31 g/mol
Now I will do some examples and you do the others:
1) NaOH: 1 atom of Na * 23 g/mol + 1 atom of O * 16 g/mol + 1 atom of H * 1 g/mol
=> 1*23g/mol + 1*16g/mol + 1*1g/mol = 40 g/mol
2) H2O
=> 2 atoms of H * 1 g/mol + 1 atom of O * 16 g/mol = 2*1g/mol + 1*16g/mol = 18 g/mol
3) Glucose: C6H12O6
6*12 g/mol + 12 * 1g/mol + 6*16 g/mol = 72g/mol + 12g/mol + 96 g/mol = 180 g/mol
4) CaSO4:
1*40 g/mol + 1*32g/mol + 4*16g/mol = 136 g/mol
Now you only have to do the last one by your own.
Explanation:
Meso compounds are optically inactive stereoisomers. Despite of having chiral carbon, they do not show optical activity because it has a plane of symmetry in its structure itself. It is superposable on its mirror image.
Aldo sugars on reaction which reducing agents such as , NaBH₄ reduces the carbonyl group in the sugar to alcohol and gives corresponding alditol.
<u>The D- aldohexose which on reduction gives a meso alditol are allose and galactose. </u>
<u>The structure is shown in the image below. Thus, in allitol and galactitol formed have internal plane of symmetry which makes the optically inactive.</u>
Answer:
The goal there is for the fruit to not get eaten, so that the seed can rely on the fruit's nutrients to support its growth.” Presumably, the strawberry went for evolutionary option number one – attract something to spread the seeds
Explanation:
Answer: We take 20 ml of 1.0 M fruit drink and add 80 ml of water to get 100 ml of 0.2 M solution.
Explanation:
According to the neutralization law,
where,
= molarity of stock solution = 0.2 M
= volume of stock solution = 100 ml
= molarity of resulting solution = 1.0 M
= volume of resulting solution = ?
Now put all the given values in the above law, we get the volume of resulting solution.
Therefore, the volume of 1.0 M required is 20 ml.
We take 20 ml of 1.0 M fruit drink and add 80 ml of water to get 100 ml of 0.2 M solution.
Mg(s) + 2HCl(aq) = H₂(g) + MgCl₂(aq)
v=300 ml=0.3 l
c=4 mol/l
n(HCl)=vc
m(H₂)/M(H₂)=n(HCl)/2
m(H₂)=M(H₂)vc/2
m(H₂)=2.0g/mol·0.3 l · 4mol/l /2 = 1.2 g
1.2 grams of hydrogen gas will be produced
