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ankoles [38]
3 years ago
13

Identify the brønsted-lowry acid, the brønsted-lowry base, the conjugate acid, and the conjugate base in each reaction: (a) c5h5

n(aq)+h2o(l)⇌c5h5nh+(aq)+oh−(aq) (b) hno3(aq)+h2o(l)⇌h3o+(aq)+no3−(aq) drag the appropriate items to their respective bins.
Chemistry
2 answers:
Pie3 years ago
7 0

acids give away protons (H+), bases accept protons, conjugate bases are what u get when when you take the protons from the acid, and conjugate acids are what u get when you add the protons to the base.

so for (a) the C5H5N is the base, water is the acid, C5H5NH+ is the conj acid, OH- is the conj base

(b) HNO3 is the acid, H2O is the base, hydronium ion is the conj. acid, NO3- is the conj base.

raketka [301]3 years ago
4 0

Answer: a) C_5H_5N(aq.)+H_2O(l)\rightarrow C_5H_5NH^+(aq.)+OH(aq.)

bronsted- lowry acid : H_2O

conjugate base : OH^-

bronsted- lowry base : C_5H_5N

conjugate acid : C_5H_5NH^+

b) HNO_3(aq)+H_2O(l)\rightarrow H_3O^+(aq.)+NO_3^-(aq.)

bronsted-lowry acid : HNO_3

conjugate base : NO_3^-

bronsted- lowry base : H_2O

conjugate acid : H_3O^+

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

For the given chemical equation:

a) C_5H_5N(aq.)+H_2O(l)\rightarrow C_5H_5NH^+(aq.)+OH(aq.)

Here, H_2O is loosing a proton, thus it is considered as a brønsted-lowry acid and after losing a proton, it forms OH^- which is a conjugate base.

And, C_5H_5N is gaining a proton, thus it is considered as a brønsted-lowry base and after gaining a proton, it forms C_5H_5NH^+ which is a conjugate acid.

b) HNO_3(aq)+H_2O(l)\rightarrow H_3O^+(aq.)+NO_3^-(aq.)

Here, HNO_3 is loosing a proton, thus it is considered as a brønsted-lowry acid and after losing a proton, it forms NO_3^- which is a conjugate base.

And, H_2O is gaining a proton, thus it is considered as a brønsted-lowry base and after gaining a proton, it forms H_3O^+ which is a conjugate acid.

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If a substance contains a hydrogen ion concentration of 1.0 x 10-5 M, which types of ions does it contain more of?
miss Akunina [59]

Since the pH of the substance is 5, the substance contains more of hydrogen ions.

<h3>What is pH of a solution?</h3>

The pH of a a solution is the negative logarithm to base ten of the hydrogen ions concentration of the solution.

pH = -log[H^{+}]

A neural solution has pH 7.

A solution with pH below 7 has more hydrogen ions while a solution with pH above 7 has more hydroxide ions.

The pH of a substance contains a hydrogen ion concentration of 1.0 x 10-5 M is 5.

Therefore, the substance contains more of hydrogen ions.

Learn more about pH at: brainly.com/question/940314

6 0
2 years ago
Looking at the stoichiometry of the reaction (see the lab manual), how many moles kmno4 must have been delivered by the buret to
timofeeve [1]
8H⁺ + 5Fe²⁺ + MnO₄⁻ ⇒ Mn²⁺ + 5Fe³⁺ + 4H₂O 
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According to the reaction, Fe</span>²⁺ and MnO4⁻<span> have following stoichiometric ratio:

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<span>
So, for each mole of </span>Fe²⁺ it is needed 1/5 moles of MnO4⁻.<span>

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7 0
3 years ago
What volume of concentrated nitric acid (15.0M) is requiredfor
seraphim [82]

Answer:

0.133 mL

Explanation:

Given data

  • Initial concentration (C₁): 15.0 M
  • Initial volume (V₁): to be determined
  • Final concentration (C₂): 0.001 M
  • Final volume (V₂): 2.00 L

We can find the volume of the concentrated solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 0.001 M × 2.00 L / 15.0 M

V₁ = 1.33 × 10⁻⁴ L = 0.133 mL

5 0
3 years ago
A solution is made by dissolving 58.125 g of sample of an unknown, nonelectrolyte compound in water. The mass of the solution is
e-lub [12.9K]

Answer:

molecular weight (Mb) = 0.42 g/mol

Explanation:

mass sample (solute) (wb) = 58.125 g

mass sln = 750.0 g = mass solute + mass solvent

∴ solute (b) unknown nonelectrolyte compound

∴ solvent (a): water

⇒ mb = mol solute/Kg solvent (nb/wa)

boiling point:

  • ΔT = K*mb = 100.220°C ≅ 373.22 K

∴ K water = 1.86 K.Kg/mol

⇒ Mb = ? (molecular weight) (wb/nb)

⇒ mb = ΔT / K

⇒ mb = (373.22 K) / (1.86 K.Kg/mol)

⇒ mb = 200.656 mol/Kg

∴ mass solvent = 750.0 g - 58.125 g = 691.875 g = 0.692 Kg

moles solute:

⇒ nb = (200.656 mol/Kg)*(0.692 Kg) = 138.83 mol solute

molecular weight:

⇒ Mb = (58.125 g)/(138.83 mol) = 0.42 g/mol

8 0
3 years ago
The pH scale ranger from
Allushta [10]

Answer:

1 -14

Explanation:

that is how it. acidity is from 1 - 6.9. 7 is neutral while 7.1- 14 is alkalinity

6 0
4 years ago
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