Identify the brønsted-lowry acid, the brønsted-lowry base, the conjugate acid, and the conjugate base in each reaction: (a) c5h5

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Identify the brønsted-lowry acid, the brønsted-lowry base, the conjugate acid, and the conjugate base in each reaction: (a) c5h5

n(aq)+h2o(l)⇌c5h5nh+(aq)+oh−(aq) (b) hno3(aq)+h2o(l)⇌h3o+(aq)+no3−(aq) drag the appropriate items to their respective bins.

Chemistry

2 answers:

Pie · Answer 1 · 2022-05-15T09:20:14+03:00

acids give away protons (H+), bases accept protons, conjugate bases are what u get when when you take the protons from the acid, and conjugate acids are what u get when you add the protons to the base.

so for (a) the C5H5N is the base, water is the acid, C5H5NH+ is the conj acid, OH- is the conj base

(b) HNO3 is the acid, H2O is the base, hydronium ion is the conj. acid, NO3- is the conj base.

raketka [301] · Answer 2 · 2022-05-15T10:59:16+03:00

Answer: a) $C_5H_5N(aq.)+H_2O(l)\rightarrow C_5H_5NH^+(aq.)+OH(aq.)$

bronsted- lowry acid : $H_2O$

conjugate base : $OH^-$

bronsted- lowry base : $C_5H_5N$

conjugate acid : $C_5H_5NH^+$

b) $HNO_3(aq)+H_2O(l)\rightarrow H_3O^+(aq.)+NO_3^-(aq.)$

bronsted-lowry acid : $HNO_3$

conjugate base : $NO_3^-$

bronsted- lowry base : $H_2O$

conjugate acid : $H_3O^+$

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

For the given chemical equation:

a) $C_5H_5N(aq.)+H_2O(l)\rightarrow C_5H_5NH^+(aq.)+OH(aq.)$

Here, $H_2O$ is loosing a proton, thus it is considered as a brønsted-lowry acid and after losing a proton, it forms $OH^-$ which is a conjugate base.

And, $C_5H_5N$ is gaining a proton, thus it is considered as a brønsted-lowry base and after gaining a proton, it forms $C_5H_5NH^+$ which is a conjugate acid.

b) $HNO_3(aq)+H_2O(l)\rightarrow H_3O^+(aq.)+NO_3^-(aq.)$

Here, $HNO_3$ is loosing a proton, thus it is considered as a brønsted-lowry acid and after losing a proton, it forms $NO_3^-$ which is a conjugate base.

And, $H_2O$ is gaining a proton, thus it is considered as a brønsted-lowry base and after gaining a proton, it forms $H_3O^+$ which is a conjugate acid.