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aksik [14]
3 years ago
6

Please check and correct if I am wrong please

Mathematics
2 answers:
Darya [45]3 years ago
8 0
They are right good job!
Vladimir [108]3 years ago
3 0
You're answers are correcy
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What are the solutions to the quadratic equation 98-x2=0
kifflom [539]

98-x^2=0\qquad\text{add}\ x^2\ \text{to both sides}\\\\98=x^2\to x^2=98\\\\x=\pm\sqrt{98}\\\\x=\pm\sqrt{49\cdot2}\\\\x=\pm\sqrt{49}\cdot\sqrt2\\\\\boxed{x=-7\sqrt2\ \vee\ x=7\sqrt2}

8 0
3 years ago
MUST HELP!!!! (25 POINTS) +BRAINLEST +5 STARS +THANKS ON PROLFILE!!!!
MrMuchimi

Answer:

Enlargement Areas

Step-by-step explanation:

if you enlarge the little one, they will intersect each other perfectly because those triangles are similar and the same. they are just different sizes

hope this helps!

3 0
3 years ago
A table measures 3.6 feet long.<br><br> How long does the table measure in inches and in yards?
sattari [20]

Answer:

43.2 inches  is  3.6ft

1.2 yards is 3.6ft

7 0
2 years ago
From a group of 13 women and ​12 men, a researcher wants to randomly select 8 women and 8 men for a study. In how many ways can
Fantom [35]

The total number of ways the study can be selected is: 637065

Given,

Total number of women in a group= 13

Total number of men in a group = 12

Number of women chosen = 8

Number of men chosen = 8

∴ the total number of ways the study group can be selected = 13C₈ and 12C₈.

This in the form of combination factor = nCr

                                                     ∴ nCr = n!/(n₋r)! r!

13C₈ = 13!/(13 ₋ 8)! 8!

        = 13!/5!.8!

        = 1287

12C₈ = 12!/(12₋8)! 8!

        = 12!/5! 8!

        = 495

Now multiply both the combinations of men and women

= 1287 × 495

= 637065

Hence the total number of ways the study group is selected is 637065

Learn more about "Permutations and Combinations" here-

brainly.com/question/11732255

#SPJ10

4 0
2 years ago
If a triangle has an area of 24 square cm what is its base if the height is 3 cm
kolezko [41]

Answer:

b=16cm .......................

3 0
3 years ago
Read 2 more answers
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