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3 years ago

8

Draw a set of objects where you can find a fractional part of the group using the total number of objects and by using subgroups

.

1 answer:

skad [1K]3 years ago

8 0

The answer is attached

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Help plz... Davidmedulla... I mean you in particular

kap26 [50]

Answer:

1. 2x

2. 22

Step-by-step explanation:

question 1

f(x)-g(x)

5x-3-(3x-3)

5x-3-3x+3

5x-3x-3+3

2x+0

2x

question 2

f(x)=y

f(-4)= -5(-4)+ (-4/-2)

= 20 + 2

=22

5 0

3 years ago

8. What's the GCF of *<br> (1 Point)<br> 4x2 - 6x + 8

Gre4nikov [31]

Answer:2

Step-by-step explanation:

6 0

3 years ago

I need help on 6-98 can you please help me

OLga [1]

Molly got 20 because she did not follow the order of operations, so this is incorrect. Nancy got the correct answer because she multiplied 4 * 3, and then added 2, giving her 14. Molly added 3+2, and multiplied that by 4. Nancy is correct with 14.

4 0

2 years ago

20 ounce sodas cost 4 for $5. How much does each soda cost?

dolphi86 [110]

I think 1.99?
I have no idea but I think it’s that

3 0

3 years ago

In 1990, the population of Boston, Massachusetts was 574,283. In 2000, the population was 589,141. What is the percent of change

MrMuchimi

Answer:

Percent of change in population is $2.6$ %

Step-by-step explanation:

Given population of Boston is $574,283$ measured in year $1990$ .

And population of Boston in year $2000$ is $589,141$ .

We need to find percent of change in population.

So, percent change $=\frac{New\ population-Old\ population}{Old\ population}\times100$ %

Here old population is $574,283$ and new population is $589,141$

Plugging these value in formula we get,

Percent change $=\frac{589,141-574,283}{574,283}\times100\\\\=\frac{14858}{574,283}\times100=0.0258\times100\\\\=2.587$

Rounding to nearest tenth 2.6%

8 0

3 years ago