Answer:
The degree is 6, and the zero is 0
Step-by-step explanation:
Hope this helps! :) ~Zane
P.S. sorry if im wrong with the zero one
3+1/x *x = 7/x*x
3x+1 = 7
3x+1-1=7-1
3x=6
3x/3 =6/3
x =2
Answer:
5 terms: m, 4, 2, -7m, 6 are the terms in question.
Step-by-step explanation:
Note that terms here are separated from one another by either + or - signs.
m + 4 consists of two terms, since m and 4 are separated by the + operator.
2 - 7m are separated by the - operator, and so there are two terms here.
Completing the counting procedure, we get:
m (first term) + 4 (second term) + 2 (third term -7m (fourth term) + 6 (fifth term).
So, if we do NOT combine like terms, we have five (5) terms altogether.
If we DO combine like terms, we end up with two (2) terms:
m -7m + 4 + 2 + 6, or -6m + 12, or two (2) terms.
The points on the graph of the inverse variation are of the form:
(x, 8/x)
<h3>
Which ordered pairs are on the graph of the function?</h3>
An inverse variation function is written as:
y = k/x.
Here we know that k = 8.
y = 8/x
Then the points (x, y) on the graph of the function are of the form:
(x, 8/x).
So evaluating in different values of x, we can get different points on the graph:
- if x = 1, the point is (1, 8)
- if x = 2, the point is (2, 4)
- if x = 3, the point is (3, 8/3)
- if x = 4, the point is (4, 2)
And so on.
If you want to learn more about inverse variations:
brainly.com/question/6499629
#SPJ1
Answer:
Step-by-step explanation:
<u />
<u>Distance formula</u>
Let P(x, y) = any point on the locus
Let A = (0, 2)
Let B = (-2, 3)
If a point moves such that its distance from (0, 2) is one third distance from (-2, 3):
Therefore, using the distance formula:
Square both sides:
![\implies x^2+(y-2)^2=\dfrac{1}{9}[(x+2)^2+(y-3)^2]](https://tex.z-dn.net/?f=%5Cimplies%20x%5E2%2B%28y-2%29%5E2%3D%5Cdfrac%7B1%7D%7B9%7D%5B%28x%2B2%29%5E2%2B%28y-3%29%5E2%5D)
Multiply both sides by 9:
