Ask question

Ask question

All categories

3 years ago

7

Tony buys 4kg of potatoes at £1.60 per kilogram and 2kg of onions at £1.80 per kilogram.

2 answers:

natali 33 [55]3 years ago

3 0

Answer:

£10

Step-by-step explanation:

4 × 1.60 = 6.40

2× 1.80 = 3.60

6.40 + 3.60 = 10.00

zhuklara [117]3 years ago

3 0

Tony buys 4kg of potatoes at £1.60 per kilogram and 2kg of onions at £1.80 per kilogram.

She pays with a £20 note.

How much change should she receive?

4kg of potatoes at £1.60 = 4 x 1.60 = 6.40

2kg of onions at £1.80 = 2 x 1.80 = 3.60

4kg of potatoes + 2kg of onions = 6.40 + 3.60 = 10

£20 - £10 = £10

How much change should she receive? £10

You might be interested in

How is 2y(z(z+5)+10) gotten from 2yz^2 +10yz +20y ? Please help!!!

Harrizon [31]

Answer:

Adding like terms! Hope this Helps!

6 0

2 years ago

What is the answer 6v(2v + 3)

Firlakuza [10]

See attached picture

Hope this helps

6 0

3 years ago

Read 2 more answers

Sort the ratios listed at the right into bins so that equivalent ratios are grouped together:

cestrela7 [59]

Step $1$

<u>Find the irreducible fraction in each ratio</u>

<u>case 1)</u> $\frac{40}{64}$

Divide by $8$ boths numerator and denominator

$\frac{40}{64}=\frac{5}{8}$

<u>case 2)</u> $\frac{5}{75}$

Divide by $5$ boths numerator and denominator

$\frac{5}{75}=\frac{1}{15}$

<u>case 3)</u> $\frac{14}{35}$

Divide by $7$ boths numerator and denominator

$\frac{14}{35}=\frac{2}{5}$

<u>case 4)</u> $\frac{24}{64}$

Divide by $8$ boths numerator and denominator

$\frac{24}{64}=\frac{3}{8}$

<u>case 5)</u> $\frac{6}{15}$

Divide by $3$ boths numerator and denominator

$\frac{6}{15}=\frac{2}{5}$

<u>case 6)</u> $\frac{65}{104}$

Divide by $13$ boths numerator and denominator

$\frac{65}{104}=\frac{5}{8}$

<u>case 7)</u> $\frac{66}{176}$

Divide by $22$ boths numerator and denominator

$\frac{66}{176}=\frac{3}{8}$

<u>case 8)</u> $\frac{12}{30}$

Divide by $6$ boths numerator and denominator

$\frac{12}{30}=\frac{2}{5}$

<u>case 9)</u> $\frac{15}{225}$

Divide by $15$ boths numerator and denominator

$\frac{15}{225}=\frac{1}{15}$

<u>case 10)</u> $\frac{6}{16}$

Divide by $2$ boths numerator and denominator

$\frac{6}{16}=\frac{3}{8}$

<u>case 11)</u> $\frac{15}{24}$

Divide by $3$ boths numerator and denominator

$\frac{15}{24}=\frac{5}{8}$

<u>case 12)</u> $\frac{48}{128}$

Divide by $16$ boths numerator and denominator

$\frac{48}{128}=\frac{3}{8}$

Step $2$

<u>Sort the ratios into bins</u>

1<u>) First Bin</u>

<u> $Ratio=\frac{5}{8}$ </u>

$\frac{40}{64}$

$\frac{65}{104}$

$\frac{15}{24}$

<u>2) Second Bin </u>

<u> $Ratio=\frac{1}{15}$ </u>

$\frac{5}{75}$

$\frac{15}{225}$

<u>3) Third Bin</u>

$Ratio=\frac{2}{5}$

$\frac{14}{35}$

$\frac{6}{15}$

$\frac{12}{30}$

4<u>) Fourth Bin</u>

<u> $Ratio=\frac{3}{8}$ </u>

$\frac{24}{64}$

$\frac{66}{176}$

$\frac{6}{16}$

$\frac{48}{128}$

3 0

2 years ago

Read 2 more answers

Suppose the total benefit of watching 1 baseball game is 100, the total benefit of watching 2 games is 120, and the total benefi

77julia77 [94]

Answer:

A. 5

Step-by-step explanation:

The marginal benefit of an article, $B_m$ is calculated as:

$B_m=\frac{DB_t}{DQ}$

Where $DB_t$ is the change in the total benefit of the article, and $DQ$ is the change in the units of the article.

If we want to know the marginal benefit of watching the 3rd game, we need to use the information of total benefit of watching 2 games and 3 games.

In this case, the total benefit of watching 2 games is 120 and the total benefit of watching 3 games is 125, so $DB_t$ and $DQ$ are equal to:

$DB_t=125-120=5$

$DQ = 3 - 2 = 1$

Then, the marginal benefit of watching the third game is:

$B_m=\frac{5}{1}=5$

4 0

3 years ago

Can you please help me 59÷2,361

telo118 [61]

If you want 59<span>÷2,361 the answer is 29.5
If you want </span>2,361÷59 the answer is <span>40.0169491525</span>

3 0

3 years ago

Read 2 more answers