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sveta [45]
2 years ago
12

Which is a counterexample for the conditional statement shown?

Mathematics
2 answers:
Sloan [31]2 years ago
3 0

Answer: Any fraction with a positive numerator and a negative denominator

Step-by-step explanation:

A counterexample in math refers to when a condition is satisfied but the result is not the conclusion that the statement said it would lead to.

In this instance, the statement is that if the numerator of the fraction is larger than the denominator, the result will be greater than 1.

If the numerator is positive and the denominator is negative then the numerator is larger than the denominator because all positive numbers are larger than negative numbers on the number line. However, the result will always be less than 1.

For instance, take the following fractions;

\frac{5}{-2}  = -2.5\\\\\frac{20}{-5} = -4\\\\\frac{50}{-10} = -5

In each case the numerator was larger than the denominator but the result was always less than 1.

Alex2 years ago
3 0

Answer:

C. any fraction with a positive numerator and a negative denominator

Step-by-step explanation:

1/-1 = -1

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3 years ago
a small rocket is shot from the edge of a cliff suppose that after t seconds the rocket is y meters above the cliff where y=30t-
Natalka [10]

Answer:

Greatest height: 45 meters

Time for greatest height: 3 seconds

Height after 5 seconds: 25 meters above the cliff

Time for height of 40 meters: 7.123 seconds

Height after 7 seconds: -35 meters (35 meters below the cliff)

Step-by-step explanation:

to find the maximum height, we need to calculate the derivative of y in relation to t and then find when dy/dt = 0:

dy/dt = 30 - 10t = 0

10t = 30

t = 3 seconds

In this time, the height is:

y = 30*3 - 5*3^2 = 45 meters

After 5 seconds, the height is:

y = 30*5 - 5*5^2 = 25 meters

The time for the height of 40 meters is:

40 = 30t - 5t^2

t^2 - 6t - 8 = 0

Using Bhaskara's formula, we have:

Delta = 6^2 + 4*8 = 68

sqrt(Delta) = 8.246

t1 = (6 + 8.246) / 2 = 7.123 seconds

t2 = (6 - 8.246) / 2 = -1.123 seconds (negative value for time is not valid)

So the time when the rocket reaches 40 meters is 7.123 seconds

After 7 seconds, the height is:

y = 30*7 - 5*7^2 = -35 meters

The rocket will be 35 meters below the cliff.

5 0
3 years ago
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3 years ago
Read 2 more answers
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