For this case we have that the following function complies with the given conditions:
To prove it, let's find the roots of the polynomial:
By doing common factor 3 we have:
Factoring the second degree polynomial we have:
Then, the solutions are:
Solution 1:
Solution 2:
Answer:
A second degree polynomial function f (x) that has a lead coefficient of 3 and roots 4 and 1 is:
A=(-36). When finding variables, try multiplying the quotient and divisor to get your dividend. Also, when multiplying/dividing negative integers, if there is one negative integer, the answer will be negative. the only exception is when multiplying/dividing two negative integers, then it would be positive. -36/9=(-4)
Three consecutive odd integers would be x, x+2, and x+4 assuming x is an odd integer. The smallest of these is x. Two times x is 2x. The greatest integer is x+4. Three times this is 3 (x+4), and if you distribute you get 3x+12. If 2x exceeds this by 15, you would make it 3x+12-15. If you add the like terms, 12+(-15) is -3. So, you have 2x=3x-3. Subtract 3x from both sides. 2x-3x is -1x, or -x. Now we have -x=-3. Divide by -, or -1 on both sides. Now we have x=3. You can substitute x for 3 for any of the consecutive odd integers to find their value.
Step-by-step explanation:
First you find out the area of the square.
Then you find the area of the circle.
After this you add the Two area together.
Four times a number would equal 4n
