<u>The mass of hydrogen atoms in the sample of water is 3.98g</u>
This can be solved by understanding of Avogadro's number and mole relationship concept.
<h3 /><h3>Avogadro's number</h3>
<u>This is a proportionality that relates the number of particles to the amount of substance in that sample and it is given as </u>![6.02*10^2^3](https://tex.z-dn.net/?f=6.02%2A10%5E2%5E3)
A molecule of water have the chemical formula as H
O. This implies that for every 1 atom or molecule of oxygen, 2 hydrogen must be present.
In the question given, we have
atoms of oxygen. This implies we must have
Now, let's compare this molar mass - Avogadro's number
molar mass of hydrogen = 1g/mol
![1g/mol=6.023*10^2^3particles\\xg=2.4*10^2^4particles\\x=\frac{1*2.4*10^2^4}{6.023*10^2^3}\\x=3.98g](https://tex.z-dn.net/?f=1g%2Fmol%3D6.023%2A10%5E2%5E3particles%5C%5Cxg%3D2.4%2A10%5E2%5E4particles%5C%5Cx%3D%5Cfrac%7B1%2A2.4%2A10%5E2%5E4%7D%7B6.023%2A10%5E2%5E3%7D%5C%5Cx%3D3.98g)
From the calculation above, we would have 3.98g of hydrogen present in that particles of oxygen.
learn more on Avogadro's concept
brainly.com/question/2761055
brainly.com/question/18706897
Explanation:
₁₄Si 1s²2s²2p⁶3s²3p².
Principal quantum number (n=3) have four electrons (3s²3p²).
2) ₁₉K 1s²2s²2p⁶3s²3p⁶4s¹.
Azimuthal quantum number (l=o) have seven electrons (1s²2s²3s²4s¹).
3) ₈₀Hg [Xe] 4f¹⁴5d¹⁰6s².
Principal quantum number (n=4) have thirty-two electrons (4s²4p⁶4d¹⁰4f¹⁴).
The principal quantum number is one of four quantum numbers which are assigned to each electron in an atom to describe that electron's state.
The azimuthal quantum number is a quantum number for an atomic orbital that determines its orbital angular momentum and describes the shape of the orbital.
that's the answer I think
Volumetric flask are calibrated to contain.