Answer:
I believe the answer is II and III
Explanation:
I'm not sure if III is right cause I cannot read the last word but I think it's OK.
Hope this helped :)
Answer:
4.2 moles of sodium cyanide (NaCN) would be needed to produce 2.1 moles of sodium sulfate (Na₂SO₄).
Explanation:
The balanced reaction is:
H₂SO₄ + 2 NaCN → 2 HCN + Na₂SO₄
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound are necessary:
- H₂SO₄: 1 mole
- NaCN: 2 moles
- HCN: 2 moles
- Na₂SO₄: 1 mole
Then you can apply the following rule of three: if by stoichiometry to produce 1 mole of sodium sulfate 2 moles of sodium cyanide are necessary, then to produce 2.1 moles of sodium sulfate how many moles of sodium cyanide are necessary?
amount of moles of sodium cyanide= 4.2 moles
<u><em>4.2 moles of sodium cyanide (NaCN) would be needed to produce 2.1 moles of sodium sulfate (Na₂SO₄).</em></u>
When determining the concentration of an acid solution, the titrant would usually be put in the burette while the analyte would be in the conical flask.
The titrant is usually a known solution while the analyte would be the unknown solution.
In order to determine the concentration of a solution of hydrofluoric acid, the acid would need to be titrated against a suitable base of known concentration using a suitable indicator to indicate the endpoint of the neutralization reaction.
Thereafter, the volume of the titrant used would be recorded and used to find the concentration of the acid (the analyte).
Thus, since the base would be known, it would be the one in the burette while the hydrofluoric acid would be the one in the conical flask.
More on titrant and analyte can be found here: brainly.com/question/22684609