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spin [16.1K]
3 years ago
15

You are presented with a white solid and told that due to careless labeling it is not clear if the substance is barium chloride,

lead chloride, or zinc chloride.when you transfer the solid to a beaker and add water,the solid dissolves to give a clear solution.next a na2so4(aq) solution is added and a white precipitate forms. what is the identity of the unknown white solid?
Chemistry
1 answer:
Lady bird [3.3K]3 years ago
5 0

The given salts are Barium chloride, lead chloride and zinc chloride.

The balanced chemical reaction between barium chloride and sodium sulfate:

BaCl_{2}(aq)+Na_{2}SO_{4}(aq)-->2NaCl(aq)+BaSO_{4}(s)_{white precipitate}

The balanced chemical reaction between lead chloride and sodium sulfate:

PbCl_{2}(aq)+Na_{2}SO_{4}(aq)-->2NaCl(aq)+PbSO_{4}(s)_{white precipitate}

The balanced chemical reaction between zinc chloride and sodium sulfate:

ZnCl_{2}(aq)+Na_{2}SO_{4}(aq)-->2NaCl(aq)+ZnSO_{4}(aq)

Both Barium chloride and lead chloride produce a white precipitate of their respective sulfates upon reaction with sodium sulfate. But BaCl2 is readily soluble in water where as Lead chloride is insoluble in water.

Therefore, the compound is barium chloride.

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Find the mass of each of these substances? 2.40 mol NaOH
damaskus [11]
Na = 23 x 2.40 = 55.2
O = 16 x 2.40 = 38.4
H = 1 x 2.40 = 2.40

55.2 + 38.4 + 2.4 = 96

2.40 mol of NaOH = 96 amu

4 0
4 years ago
If 4.168 kJ of heat is added to a calorimeter containing 75.40 g of water, the temperature of the water and the calorimeter incr
Alinara [238K]

Answer:

The value of  the heat capacity of the Calorimeter  C_c = 54.4 \frac{J}{c}

Explanation:

Given data

Heat added Q = 4.168 KJ = 4168 J

Mass of water m_w = 75.40 gm

Temperature change = ΔT = 35.82 - 24.58 = 11.24 ° c

From the given condition

Q = m_w C_w ΔT + C_c ΔT

Put all the values in above equation we get

4168 = 75.70 × 4.18 × 11.24 +  C_c × 11.24

611.37 =  C_c × 11.24

C_c = 54.4 \frac{J}{c}

This is the value of  the heat capacity of the Calorimeter.

7 0
3 years ago
Which table correctly identifies the subatomic particle's charge and mass?<br> a<br> b<br> c<br> d
s344n2d4d5 [400]
It’s b that charts say it
8 0
3 years ago
Every day on his ride to school, Max sees some sedimentary rock. He starts to wonder: Could material from this sedimentary rock
Sloan [31]

Material from this sedimentary rock ever forms igneous rock, <u>Option D. Yes, if the sedimentary rock is moved below Earth’s outer layer and exposed to energy from Earth’s interior, it can melt into liquid rock and form </u><u>igneous rock.</u>

Sedimentary rocks are shaped from pre-existing rocks or pieces of soon-as-dwelling organisms. They form from deposits that collect on this planet's floor. Sedimentary rocks regularly have special layering or bedding.

Igneous rock, or magmatic rock, is one of the 3 primary rock kinds, the others being sedimentary and metamorphic. Igneous rock is shaped via the cooling and solidification of magma or lava. The magma may be derived from partial melts of existing rocks in either a planet's mantle or crust.

Learn more about igneous rocks here:-brainly.com/question/6533375

#SPJ1

<u>Disclaimer:- your question is incomplete, please see below for the complete question.</u>

Every day on his ride to school, Max sees some sedimentary rock. He starts to wonder: Could material from this sedimentary rock ever form igneous rock?

A. No, igneous rock can only form out of other igneous rocks. Sedimentary rock cannot change into igneous rock.

B. No, igneous rock forms under Earth’s outer layer due to energy from Earth’s interior, but the sedimentary rock is only at Earth’s surface.

C. Yes, if the sedimentary rock is exposed to energy from the sun at Earth’s surface for a long enough time, it can melt into liquid rock and form igneous rock.

D. Yes, if the sedimentary rock is moved below Earth’s outer layer and exposed to energy from Earth’s interior, it can melt into liquid rock and form igneous rock.

3 0
1 year ago
How many grams Glycylglycine (molecular mass 132.119 grams/mole) are required to make 1 liter at 0.5 Molar concentration. If you
SOVA2 [1]

Explanation:

The given data is as follows.

        Concentration of solution = 0.5 M

        Volume of solution = 1 L

Molar mass of Glycylglycine = 132.119 g/mol

As molarity is the number of moles present in liter of solvent.

Mathematically,      Molarity = \frac{\text{No. of moles}}{\text{Volume}}

Hence, calculate the number of moles as follows.

            No. of moles = Molarity × Volume

                                  = 0.5 M \times 1 L

                                  = 0.5 mol

Therefore, mass of glycylglycine = mol × molar mass

                                                      = 0.5 mol \times 132.119 g/mol

                                                      = 66.06 g

Thus, we can conclude that 66.06 g glycylglycine is required.

8 0
4 years ago
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