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suter [353]
3 years ago
5

¿Cuál(es) de las siguientes propiedades aumentan a más Z en un grupo?

Chemistry
1 answer:
liq [111]3 years ago
5 0

Answer:

The correct answer is c) Electronegativity

Explanation:

The Z corresponds to the atomic number (defines the number of protons in the nucleus and also the electrons present in the atom). The Z increases from left to right in the same period, this is due to less shielding of the electrons in the last layer. Electronegativity (defined as the ability of the atoms to attract, in a covalent chemical bond, the electrons that it shares with other atoms), increases, the greater the Z (there is less distance).

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Fill in the blanks and balance with the correct coefficient​
MrRissso [65]

\huge\mathrm{  \underline{Answer}}࿐

The Balanced equation will be :

\mathrm{ \boxed2Fe +  \boxed3Cl_2  \rightarrow  \boxed2FeCl_3}

The Coefficients are :

  • Fe - 2

  • Cl_2 - 3

  • FeCl_3 - 2

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4 0
2 years ago
Physical activity and exercise typically lead to __________.
polet [3.4K]
<span>Physical activity and exercise typically lead to higher energy levels. As your body gets used to working hard consistently, you tend to be more prepared and in better physical condition. Your body begins to learn that you should burn up calories quickly to prepare to be active, and this results in increased energy levels even when you're not currently exercising.</span>
6 0
3 years ago
Read 2 more answers
Which element has the ground state electron configuration 1s22s22p63s23p3?
Natalka [10]
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4 0
3 years ago
What is the formula used to calculate the heat required to warm or cool one phase of matter
Ronch [10]

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4 0
3 years ago
For the following reaction, 4.31 grams of iron are mixed with excess oxygen gas . The reaction yields 5.17 grams of iron(II) oxi
natka813 [3]

<u>Answer:</u> The theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}       ....(1)

  • <u>For Iron:</u>

Given mass of iron = 4.31 g

Molar mass of iron = 53.85 g/mol

Putting values in above equation, we get:  

\text{Moles of iron}=\frac{4.31g}{53.85g/mol}=0.0771mol

For the given chemical reaction:

2Fe(s)+O_2(g)\rightarrow 2FeO(s)

By Stoichiometry of the reaction:

2 moles of iron produces 2 moles of iron (ii) oxide.

So, 0.0771 moles of iron will produce = \frac{2}{2}\times 0.0771=0.0771mol of iron (ii) oxide

Now, calculating the theoretical yield of iron (ii) oxide using equation 1, we get:

Moles of of iron (II) oxide = 0.0771 moles

Molar mass of iron (II) oxide = 71.844 g/mol

Putting values in equation 1, we get:  

0.0771mol=\frac{\text{Theoretical yield of iron(ii) oxide}}{71.844g/mol}=5.53g

To calculate the percentage yield of iron (ii) oxide, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of iron (ii) oxide = 5.17 g

Theoretical yield of iron (ii) oxide = 5.53 g

Putting values in above equation, we get:

\%\text{ yield of iron (ii) oxide}=\frac{5.17g}{5.53g}\times 100\\\\\% \text{yield of iron (ii) oxide}=93.49\%

Hence, the theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

7 0
2 years ago
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