Mass of Oxygen required : 24 grams
<h3>Further explanation</h3>
Given
3 moles of H
1.5 moles of O
3 moles of H₂O
Required
Mass of O
Solution
Reaction
2H₂ + O₂ ⇒ 2H₂O
Mass of Oxygen for 1.5 moles of O :
= mol x Ar O
= 1.5 moles x 16 g/mol
= 24 grams
Answer: 1. 1.59 x 10^23 Particles
2. 4.79 x 10^21 particles
3. 2.67 x 10^25 particles
4. 2.12 x 10^23 Particles
Explanation: 1mole of any substance contains 6.02x10^23 Particles
1. 0.264 mol of silver will contain = 0.264 x 6.02x10^23 = 1.59 x 10^23 Particles
2. 7.95 x 10^-3 mol sodium chloride will contain = 7.95 x 10^-3 X 6.02x10^23 = 4.79 x 10^21 particles
3. 44.4 mol carbon dioxide will contain = 44.4 x 6.02x10^23 = 2.67 x 10^25 particles
4. 0.352 mol nitrogen will contain = 0.352 x 6.02x10^23 = 2.12 x 10^23 Particles
<span>The correct answer is, Alkali Metals</span>
There are 6.21371192 miles in 1mil cm
Substance that undergoes a change in a chemical reaction is
c. A reactant
