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3 years ago

¿Cuál(es) de las siguientes propiedades aumentan a más Z en un grupo?

Chemistry

1 answer:

liq [111]3 years ago

5 0

Answer:

The correct answer is c) Electronegativity

Explanation:

The Z corresponds to the atomic number (defines the number of protons in the nucleus and also the electrons present in the atom). The Z increases from left to right in the same period, this is due to less shielding of the electrons in the last layer. Electronegativity (defined as the ability of the atoms to attract, in a covalent chemical bond, the electrons that it shares with other atoms), increases, the greater the Z (there is less distance).

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Which profession is likely to use a radiation shield?

pantera1 [17]

Which profession is likely to use a radiation shield?
A.)dentist
B.)astronomer
C.)mathematician
D.)geologist

The answer is B: Astronomer

3 0

3 years ago

Read 2 more answers

What is a colligative property?

V125BC [204]

Colligative properties are properties of solutions that depend on the number of molecules [or ions] in a given volume of solvent and not on the properties (e.g. size or mass) of the compound. Colligative properties include: lowering of vapor pressure; elevation of boiling point; depression of freezing point and osmotic pressure.

6 0

3 years ago

For the reaction of hydrogen with iodine

fenix001 [56]

Answer:

$r_{H_2} = \frac{-1}{2} r_{HI}$

Explanation:

Hello!

In this case, considering the given chemical reaction:

$H_2(g) + I_2(g) \rightarrow 2HI(g)$

Thus, by applying the law of rate proportions, we can write:

$\frac{1}{-1} r_{H_2} = \frac{1}{-1}r_{i_2} = \frac{1}{2} r_{HI}$

Whereas the stoichiometric coefficients of reactants are negative due their disappearance and that of the product is positive due to its appearance. In such a way, when we relate the rate of disappearance of hydrogen gas to the rate of formation of hydrogen iodide, we obtain:

$r_{H_2} = \frac{-1}{2} r_{HI}$

Best regards!

8 0

2 years ago

Titration of 0.824 g of potassium hydrogen phthalate required 38.314 g of naoh solution to reach the end point detected by pheno

melamori03 [73]

1.062 mol/kg.

Step 1. Write the balanced equation for the neutralization.

MM = 204.22 40.00

KHC8H4O4 + NaOH → KNaC8H4O4 + H2O

Step 2. Calculate the moles of potassium hydrogen phthalate (KHP)

Moles of KHP = 824 mg KHP × (1 mmol KHP/204.22 mg KHP)

= 4.035 mmol KHP

Step 3. Calculate the moles of NaOH

Moles of NaOH = 4.035 mmol KHP × (1 mmol NaOH/(1 mmol KHP)

= 4.035 mmol NaOH

Step 4. Calculate the mass of the NaOH

Mass of NaOH = 4.035 mmol NaOH × (40.00 mg NaOH/1 mmol NaOH)

= 161 mg NaOH

Step 5. Calculate the mass of the water

Mass of water = mass of solution – mass of NaOH = 38.134 g - 0.161 g

= 37.973 g

Step 6. Calculate the molal concentration of the NaOH

b = moles of NaOH/kg of water = 0.040 35 mol/0.037 973 kg = 1.062 mol/kg

3 0

3 years ago

In a cold pack, which type of reaction draws heat from the surroundings?

Bingel [31]

That would be an endothermic reaction! :)

6 0

3 years ago