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anastassius [24]
4 years ago
8

How much heat, in joules and in calories, is required to heat 28.4g ice cube from -23 to -1

Chemistry
1 answer:
Salsk061 [2.6K]4 years ago
5 0

<u>Given:</u>

Mass of ice cube, m = 28.4 g

Initial temperature, T1 = -23 C

Final temperature, T2 = -1 C

<u>To determine:</u>

Heat required to raise the temperature from T1 to T2

<u>Explanation:</u>

Heat required (Q) is given as:

Q = mcΔT = mc(T2-T1)

where c = specific of ice (water) = 4.182 J/g C

Q = 28.4 * 4.182*(-1-(-23)) = 2612.9 J

Since 1 J = 0.239 cal

The corresponding Q = 0.239*2612.9 = 624.48 cal

Ans: Q = 2612.9 J

        Q = 624.4 cal

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