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Katena32 [7]
3 years ago
6

The periodic table is useful because it is organized to show many patterns and trends. What property shows a decrease moving fro

m the bottom of Group 3 to the top of Group 3?
Chemistry
1 answer:
Alex73 [517]3 years ago
3 0

Atomic radius

Explanation:

A decrease in moving from the bottom of Group 3 to the top of the group shows an increase in trend from top to bottom.

The atomic radius of elements increases from top to bottom and decreases from the bottom to the top.

The elements in group 3 are B, Al , Ga, In and Tl

  • Atomic radius is taken as half of the inter-nuclear distance between two covalently bonded atoms of non-metallic elements or half of the distance between two nuclei in the solid state of metals.
  • Downs a group from top to bottom, atomic radii increases progressively due to successive shells being added.
  • This compensates for the size reducing effect of the increased nuclear charge.

learn more:

Atomic radii brainly.com/question/5048216

#learnwithBrainly

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Students experiment with the flow of
OleMash [197]
Rubber is not very good at conducting electricity. This is because rubber makes it difficult for electrons to flow between atoms, due to rubber having tightly packed electrons. Materials like rubber are known as insulators.
Conductors are the opposite, they conduct electricity very well. Examples of conductors are metal, which is why metal is used in wires.
Since rubber is not a conductor, answer choice B can be eliminated. This can also eliminate answer choice D, since insulators like rubber don't allow electricity to easily flow.
While rubber gloves keep our hands dry, there are no liquids involved in this experiment and this is not the main reason for using rubber gloves. This eliminates answer choice C.

The answer is A. rubber gloves are insulators.
The teacher instructs the students to wear rubber gloves to prevent them from getting an electric shock.

Answer:
A. rubber gloves are insulators

Hope this helps!
5 0
3 years ago
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Which statement correctly describes the actual yield and the theoretical yield of a reaction? (1 point)
Furkat [3]

Answer:

C: The actual yield depends on the reaction conditions, but the theoretical yield varies only with reactant amounts

Explanation:

Looking at the options, the correct one is Option C because the actual yield usually depends on the conditions of the reaction, while the theoretical yield usually varies with only the amount of reactant.

8 0
3 years ago
What is the entropy of this collection of training examples with respect to the positive class B. What are the information gains
Alenkinab [10]

The data set is missing in the question. The data set is given in the attachment.

Solution :

a). In the table, there are four positive examples and give number of negative examples.

Therefore,

$P(+) = \frac{4}{9}$   and

$P(-) = \frac{5}{9}$

The entropy of the training examples is given by :

$ -\frac{4}{9}\log_2\left(\frac{4}{9}\right)-\frac{5}{9}\log_2\left(\frac{5}{9}\right)$

= 0.9911

b). For the attribute all the associating increments and the probability are :

  $a_1$   +   -

  T   3    1

  F    1    4

Th entropy for   $a_1$  is given by :

$\frac{4}{9}[ -\frac{3}{4}\log\left(\frac{3}{4}\right)-\frac{1}{4}\log\left(\frac{1}{4}\right)]+\frac{5}{9}[ -\frac{1}{5}\log\left(\frac{1}{5}\right)-\frac{4}{5}\log\left(\frac{4}{5}\right)]$

= 0.7616

Therefore, the information gain for $a_1$  is

  0.9911 - 0.7616 = 0.2294

Similarly for the attribute $a_2$  the associating counts and the probabilities are :

  $a_2$  +   -

  T   2    3

  F   2    2

Th entropy for   $a_2$ is given by :

$\frac{5}{9}[ -\frac{2}{5}\log\left(\frac{2}{5}\right)-\frac{3}{5}\log\left(\frac{3}{5}\right)]+\frac{4}{9}[ -\frac{2}{4}\log\left(\frac{2}{4}\right)-\frac{2}{4}\log\left(\frac{2}{4}\right)]$

= 0.9839

Therefore, the information gain for $a_2$ is

  0.9911 - 0.9839 = 0.0072

$a_3$     Class label      split point       entropy        Info gain

1.0         +                        2.0            0.8484        0.1427

3.0        -                         3.5            0.9885        0.0026

4.0        +                        4.5            0.9183         0.0728

5.0        -

5.0        -                        5.5            0.9839        0.0072

6.0        +                       6.5             0.9728       0.0183

7.0        +

7.0        -                        7.5             0.8889       0.1022

The best split for $a_3$  observed at split point which is equal to 2.

c). From the table mention in part (b) of the information gain, we can say that $a_1$ produces the best split.

4 0
3 years ago
Which of the following statements about 13C NMR is not true?A. In 13C proton-decoupled NMR spectra, all peaks are singlets.B. 13
adoni [48]

Answer: .B. 13C NMR spectra display peaks for only carbons that bear hydrogen atoms.

Explanation:

The statements that are true about 13C NMR are:

A. In 13C proton-decoupled NMR spectra, all peaks are singlets.

C 13C NMR chemical shifts occur over a greater range than 1H NMR chemical shifts.

D. 13C NMR easily differentiates between the different hybridized carbons (sp3, sp2, and sp hybridized carbons).organic-chemistry

Therefore, the option that isn't true is option B. "13C NMR spectra display peaks for only carbons that bear hydrogen atoms". This is false because 13C NMR will show every peak in the spectrum and it doesn't matter if it's only carbons that bear hydrogen atoms as everything will be shown.

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A GFCI is an example of what kind of electrical safety device?
vichka [17]

Answer:

Circuit breaker.

Explanation:

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