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strojnjashka [21]
3 years ago
6

Which choice below would affect the rate of reaction in the opposite way from the other four?

Chemistry
1 answer:
bulgar [2K]3 years ago
4 0
Adding a catalyst as this would speed up the reaction and the rest would slow it down
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How many grams of oxygen are required to react with 12.0 grams of octane(C8H18) in the combustion of octane in gasoline?
solniwko [45]

Answer : 42 grams of oxygen are required.

Explanation :

Step 1 : Write balanced chemical equation.

The combustion reaction of octane with oxygen can be written as,

2 C_{8}H{18} (g)  + 25  O_{2} (g) \rightarrow 16 CO_{2} (g) +18  H_{2}O (g)

Step 2 : Find moles of octane.

The given mass of octane is 12 g

Molar mass of octane is 114.2 g/mol

The moles of octane are calculated as,

moles =\frac{grams}{MolarMass}  =\frac{12g}{114.2g/mol}  = 0.105 mol

We have 0.105 mol octane.

Step 3: Use mole ratio from balanced equation to find moles of O₂

The mole ratio of octane and O₂ is 2 : 25. Let us use this as a conversion factor.

0.105 mol C_{8}H_{18} \times\frac{25mol O_{2}}{2molC_{8}H_{18}}  = 1.31 mol

We have 1.31 mol O₂.

Step 4 : Convert moles of O₂ to grams.

The molar mass of O₂ is 32 g/mol.

The grams of O₂ can be calculated as,

1.31 mol O_{2} \times\frac{32g}{mol}  = 42 grams

42 grams of oxygen are required.

8 0
3 years ago
Put the elements in order from the highest electronegativity at the top of your list, to the lowest at the bottom.
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Br
Se
As
Ge
Ga
Rb
Elements in the top right corner of the periodic table have the highest electronegativity. Elements on the right side have a higher electronegativity than those on the left, same with the ones on the top in comparison to those on the bottom. 
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Answer:

Yes

Explanation:

As long as its a solid, you can count it. It will be hard, but possible.

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I believe it is Spruce, because of the shape of the leaves

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