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3 years ago

5

Y-2=4 (x-1) in Standard form and steps

1 answer:

djverab [1.8K]3 years ago

8 0

Ax+by=c is standard form, so first, you need to distribute the 4 to inside the parenthesis, so now the equation becomes y-2 = 4x-4, next you need to get x and y on the same side and get the c variable onto the right side of the equation, subtract 4x from both sides, now we have y-2-4x =-4, now add 2 to both sides to get c by itself. Now the equation should look like this, -4x+y=-2. This is the equation now in standard form. Hope this helps.

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max said that 36594 is less than 5980 because 3 is less then 5 describe max's error and give the correct answer

Verizon [17]

He was wrong because, although three is greater than five, the value of the three is in the ten thousands place, while the five is in the thousands place. Therefore, the correct answer would be that 36594 is greater than 5980.

4 0

3 years ago

Find the volume of the largest rectangular box in the first octant with three faces in the coordinate planes and one vertex in t

Tresset [83]

Answer: The volume of largest rectangular box is 4.5 units.

Step-by-step explanation:

Since we have given that

Volume = $xyz$

with subject to $x+2y+3z=9$

So, let $z=\dfrac{9-x-2y}{3}$

So, Volume becomes,

$V=xyz\\\\V=xy(\dfrac{9-x-2y}{3})\\\\V=\dfrac{9xy-x^2y-2xy^2}{3}$

Partially derivative wrt x and y we get that

$9-2x-2y=0\implies 2x+2y=9\\\\and\\\\9-x-4y=0\implies x+4y=9$

By solving these two equations, we get that

$x=3,y=\dfrac{3}{2}$

So, $z=\dfrac{9-x-2y}{3}=\dfrac{9-3-3}{3}=\dfrac{3}{3}=1$

So, Volume of largest rectangular box would be

$xyz=3\times \dfrac{3}{2}\times 1=\dfrac{9}{2}=4.5$

Hence, the volume of largest rectangular box is 4.5 units.

4 0

3 years ago

List numbers that have 24 as a multiple

Vilka [71]

2,12, 1 ,24,3,8,4,3,6,
THese number has 24 as a multiple so they are actually factors
~JZ
Hope it helps

4 0

3 years ago

Read 2 more answers

The kinetic energy (K) that an object has varies jointly with its mass (m) and the square of its velocity (v). The equation that

lord [1]

The kinetic energy of the bowling ball with the mass and traveling at the given velocity is 10.14 Joules.

<h3>What is Kinetic Energy?</h3>

Kinetic energy is simply a form of energy a particle or object possesses due to its motion.

It is expressed as;

K = (1/2)mv²

Where m is mass of the object and v is its velocity.

Given that;

Mass of the bowling ball m = 3kg

Velocity of the bowling ball v = 2.6m/s

Kinetic energy K = ?

We substitute the given values into the above equation.

K = (1/2)mv²

K = 0.5 × 3kg × (2.6m/s)²

K = 0.5 × 3kg × 6.76m²/s²

K = 10.14kgm²/s²

K = 10.14J

Therefore, the kinetic energy of the bowling ball with the mass and traveling at the given velocity is 10.14 Joules.

Learn more about kinetic energy here: brainly.com/question/12669551

#SPJ1

6 0

2 years ago

I need to solve the whole thing

kipiarov [429]

1.) 40, 2.) 8, 3.) 18, 4.) 15, 8.) 12, 9.) 30, 10.) 72, 11.) 36

4 0

3 years ago