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3 years ago

What is the chemical formula for sodium sulfate? (1) Na2SO3 (3) NaSO3 (2) Na2SO4 (4) NaSO4

Chemistry

1 answer:

Gelneren [198K]3 years ago

3 0

The chemical formula for Sodium Sulfate is Na2SO4.

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Deep sea divers use a mixture of helium and oxygen to breathe. Assume that a diver is going to a depth of 150 feet where the tot

Svetlanka [38]

Answer:

4.525% is the percentage by volume of oxygen in the gas mixture.

Explanation:

Total pressure of the mixture = p = 4.42 atm

Partial pressure of the oxygen = $p_1=0.20 atm$

Partial pressure of the helium = $p_2$

$p_1=p\times \chi_1$ (Dalton law of partial pressure)

$0.20 atm=4.42 atm\times \chi_1$

$\chi_1=\frac{0.20 atm}{4.42 atm}=0.04525$

$\chi_2=1-\chi_1=1-0.04525=0.95475$

$chi_1+chi_2=1$

$n_1=0.04525 mol,n_2=0.95475 mol$

According Avogadro law:

$Moles\propto Volume$ (At temperature and pressure)

Volume occupied by oxygen gas = $V_1$

Total moles of gases = n = 1 mol

Total Volume of the gases = V

$\frac{n_1}{V_1}=\frac{n}{V}$

$\frac{V_1}{V}=\frac{n_1}{n}=\frac{0.04525 mol}{1 mol}$

Percent by volume of oxygen in the gas mixture:

$\frac{V_1}{V}\times 100=\frac{0.04525 mol}{1 mol}\times 100=4.525\%$

6 0

4 years ago

A container of gas has a volume of 3.5 L and a pressure of 0.8 atm. Assuming the temperature remains constant, what volume of ga

vovikov84 [41]

<h3>Answer:</h3>

5.6 L

<h3>Explanation:</h3>

We are given;

Initial volume, V1 = 3.5 L
Initial pressure, P1 = 0.8 atm
Final pressure, P2 = 0.5 atm

We are required to calculate the final volume;

According to Boyle's law, the volume of a fixed mass of a gas and the pressure are inversely proportional at a constant temperature.

That is; P α 1/V
Mathematically, P=k/V
At two different pressure and volume;

P1V1 = P2V2

In this case;

Rearranging the formula;

V2 = P1V1 ÷ P2

= (0.8 atm × 3.5 L) ÷ 0.5 atm

= 5.6 L

Therefore, the resulting volume is 5.6 L

7 0

3 years ago

In order to improve their recovery after an intense workout many high-level athletes do "cool downs" to slow their movements, ea

Iteru [2.4K]

Answer:

This question is so confusing, I'm sorry

8 0

3 years ago

What is the enthalpy change (in kJ) of a chemical reaction that raises the temperature of 250.0 ml of solution having a density

stellarik [79]

Answer:

328.4KJ

Explanation:

Before we move on to calculate enthalpy change, we calculate the amount of heat Q

Q= mcΔT

m = density * volume = 250 * 1.25 = 312.5g

c = 3.74J/g.k

ΔT = 7.80 + 273.15K = 280.95K

Q= 312.5 * 3.74 * 280.95 = 328,360.312 J= 328.4KJ(1000J = 1KJ, so divide by 1000)

The enthalpy change in the reaction is same as amount of heat transferred = 328.4KJ

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4 years ago

Some properties, like boiling point elevation and freezing point depression, change in solutions due to the presence and number

Reil [10]

D. quantitative properties

Boiling point and freezing point depression are both values that can be represented quantitatively (in number form).

5 0

3 years ago

Read 2 more answers