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Reptile [31]
3 years ago
15

A solar panel measures 0.57 m by 1.3 m. In direct sunlight, the panel delivers 6.6 A at 6 V. If the intensity of sunlight is 300

W/m2, what is the efficiency, as a percentage, of the solar panel in converting solar energy into electrical energy?
Physics
1 answer:
zheka24 [161]3 years ago
8 0

Answer:

efficiency of solar panel is 18%

Explanation:

Energy received by the sunlight is given as

Power = intensity \times area

here we know the dimensions of the plate as

L = 0.57 m

W = 1.3 m

now we have

Area = (0.57)(1.3) m^2

A = 0.741 m^2

now the power received by the sun light is given as

P_1 = 0.741(300) = 222.3 W

now the output power due to solar panel is given as

P_{out} = V i

P_{out} = (6.6 A)(6 V)

P_{out} = 39.6 Watt

now the efficiency is given as

\eta = \frac{P_{out}}{P_{in}}

\eta = \frac{39.6}{222.3}

\eta = 0.18

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