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Irina18 [472]
3 years ago
8

How are stars important to the Milky Way

Physics
2 answers:
Elza [17]3 years ago
6 0
Stars are a source of light and heat. They recycle all the matter, gas, and dust and process them into new material. They were created as a major driving force of evolution of the universe. 
PolarNik [594]3 years ago
4 0
Stars are the light and heat of the milky way the stars work with the milky way like the sun works with the earth the stars keep the milky way lit up and semi  warm like how the sun (which is a star of the milky way )  keeps the earth warm. Just remember that stars r just very big balls of gas burning in the sky :)
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how does inertia explain the movement of your body when a car in which you are riding comes to a sudden stop? (8 sentences)
nydimaria [60]
Your body continues to move unless stopped by the seatbelt. An object in motion will remain in motion. Since your body was already moving it will continue to.
5 0
3 years ago
A string is wound tightly around a fixed pulley having a radius of 5.0 cm. as the string is pulled, the pulley rotates without a
lubasha [3.4K]
The angular speed can be solve using the formula:
w = v / r
where w is the angular speed
v is the linear velocity
r is the radius of the object

w = ( 5 m / s ) / ( 5 cm ) ( 1 m / 100 cm )
w = 100 per second
8 0
3 years ago
Read 2 more answers
An aquarium open at the top has 30-cm-deep water in it. You shine a laser pointer into the top opening so it is incident on the
Setler [38]

Answer:

You must add 8cm of water to the tank

Explanation:

In order to find how much the height is we will use the Snell Refraction law

.

This law relates the index of refraction of the water (n2), the index of refraction of the air (n1), the incidence angle relative to the vertical (theta1) and the refraction angle relative to the vertical (theta2) by using the next equation:

(n1)*(sin(theta1))=(n2)*(sin(theta2))

Then we will find the refraction angle relative to the vertical this way:

(n1/n2)*(sin(theta1))=sin(theta2)

(1/1.33)*(sin(45))=sin(theta2)

Then, theta2=32.12°

Now that we have this information we can imagine a triangle with a 30cm height and a 32.12° angle. This way we can find how much X is, this X will be the distance between the vertical line and the spot the beam hits the bottom, so we can use some trigonometry to find it, this way:

tan(32.12)=(X/30cm)

X=(tan(32.12))*(30cm)

Then, X=18.8cm, we can approximate it to 19cm

Once we have X we will add 5cm to it which is how much the beam needs to be moved, then the new X will be 24cm

Now, with the new horizontal distance we will find the new vertical distance, let´s call it Y, this way we will know how much water we must add to move the beam, then we will have a triangle with a vertical distance called Y, the same 32.12° angle will be used as we are still working with the air-water interface and a 19cm horizontal distance, then:

tan(32.12)=(24cm/Y)

Y=(24cm/tan(32.12))

Then, Y=38cm

In this case, you must add 8cm of water to the tank to move the beam on the bottom 5cm

5 0
3 years ago
In the academic year of 2012-2013, how many student athletes had some or all of their education paid for?
klio [65]

Answer:1,000,000 Kids

Explanation:Dragon

6 0
2 years ago
An athlete competing in long jump leaves the ground with a speed of 9.14 m/s at an angle of 35.00 above the horizontal. What is
Lemur [1.5K]

Answer:

      R = 8.01 m

Explanation:

We can solve this problem using the projectile launch equations. The jump length is the throw range

           R = v₀² sin  2θ / g

in the exercise they give us the initial speed of 9.14 m / s and in the launch angle 35º

let's calculate

           R = 9.14² sin (2  35) / 9.8

           R = 8.01 m

this is the jump length

5 0
3 years ago
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