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tekilochka [14]
4 years ago
15

"Compared to infrared radiation, does ultraviolet radiation have longer or shorter wavelengths? Does ultraviolet radiation have

higher or lower energy per photon?"
Physics
1 answer:
balu736 [363]4 years ago
5 0

Answer:Ultraviolet radiation has shorter wavelengths and higher energy than infrared radiation.

Explanation: Electromagnetic radiation radiations which have both electrical and magnetic properties,they can be transmitted through space or through a medium.

It includes Gamma radiation, infra-red, visible light, Ultraviolet radiation etc they occur with different wavelength, the lower the wavelength the higher the Energy dissipated per photon. According to their order of decreasing wavelength and increased energy they are classified as follows.

RADIO WAVE, MICRO WAVE, INFRA-RED, VISIBLE LIGHT, ULTRAVIOLET RAY, X-RAY, GAMMA RAYS.

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Describe the role of observations in scientific endeavor and explain the characteristics of good observations.
koban [17]
Observations are used in order to collect data and record a variety of interesting or useful key points about the subject or specimen in observation. These observations, if made well, can be recorded and used to supplement a hypothesis. 
3 0
3 years ago
What type of nuclear decay occurs when the original nucleus loses two protons and two neutrons?
Igoryamba
THe loss of 2 protons and 2 neutrons (also called a helium nucleus) is defined as alpha decay.
3 0
3 years ago
identify a major advantage and a major disadvantage of using a renewable resources to produce electricity
STatiana [176]
Advantage: It's often cleaner (better for the environment)
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4 0
4 years ago
Read 2 more answers
A 56 kg astronaut stands on a bathroom scale inside a rotating circular space station. The radius of the space station is 250 m.
Zielflug [23.3K]

Answer:

The speed of space station floor is 49.49 m/s.

Explanation:

Given that,

Mass of astronaut = 56 kg

Radius = 250 m

We need to calculate the speed of space station floor

Using centripetal force and newton's second law

F=mg

\dfrac{mv^2}{r}=mg

\dfrac{v^2}{r}=g

v=\sqrt{rg}

Where, v = speed of space station floor

r = radius

g = acceleration due to gravity

Put the value into the formula

v=\sqrt{250\times9.8}

v=49.49\ m/s

Hence, The speed of space station floor is 49.49 m/s.

6 0
3 years ago
Assuming a nearly frictionless ride, what can you say about a roller coaster’s potential and kinetic energy from the top to the
ArbitrLikvidat [17]
The mechanical energy of the roller coaster is sum of kinetic energy K and gravitational potential energy U:
E=K+U
where
K= \frac{1}{2}mv^2 is the kinetic energy
U=mgh is the gravitational potential energy

Since the ride is frictionless, the total mechanical energy E is conserved during the ride. Therefore, at the top of the hill, the potential energy is maximum, because h (the height) is maximum, and this means the kinetic energy is minimum (because the sum of K and U is constant), so the velocity will be minimum. Viceversa, at the bottom of the hill, the potential energy will be minimum (because h is minimum), so the kinetic energy K will be maximum, and the velocity v of the roller coaster will be maximum.
4 0
3 years ago
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