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skad [1K]
3 years ago
9

A ball is released at the top of a ramp at t =0. which is the speed of the ball at t=4

Physics
2 answers:
Semmy [17]3 years ago
6 0
Accel;eration due to gravity= 9.8m/s^2. Initial velocity = 0(given). Time=4. Applying kinematic equation v=u+at, v= 0 + 9.8x4 = 39.2. Therefore speed of the ball after t=4 is 39.2
vodka [1.7K]3 years ago
3 0
AbhiGhost your answer would be right if we were talking about free fall. The force that is providing the acceleration is Fx=mgsinФ, where Ф is the angle the ramp makes with the horizontal.
Fx=ma=mgsinФ
Hence:
a=gsinФ.
And the speed is v=a*t=gsinФ*t.
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The energy associated with the random motion of molecules or atoms within a substance is
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Someone please help with this
SSSSS [86.1K]

Answer:

<em>The new force is 2/3 of the original force</em>

Explanation:

<u>Coulomb's Law </u>

The electrical force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.

Written as a formula:

\displaystyle F=k\frac{q_1q_2}{d^2}

Where:

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d= The distance between the objects

Suppose the first charge is doubled (2q1) and the second charge is one-third of the original charge (q2/3). Now the force is:

\displaystyle F'=k\frac{2q_1*q_2/3}{d^2}

Factoring out 2/3:

\displaystyle F'=\frac{2}{3}k\frac{q_1*q_2}{d^2}

Substituting the original force:

F'=\frac{2}{3}F

The new force is 2/3 of the original force

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Read 2 more answers
You need to determine the density of a ceramic statue. If you suspend it from a spring scale, the scale reads 28.4 NN . If you t
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Answer:

2491.23 kg/m³

Explanation:

From Archimedes principle,

R.d = weight of object in air/ upthrust in water = density of the object/density of water

⇒ W/U = D/D' ....................... Equation 1

Where W = weight of the ceramic statue, U = upthrust of the ceramic statue in water, D = density of the ceramic statue, D' = density of water.

Making D the subject of the equation,

D = D'(W/U).................... Equation 2

Given: W = 28.4 N, U = lost in weight = weight in air- weight in water

U = 28.4 - 17.0 = 11.4 N,

Constant: D' = 1000 kg/m³.

Substitute into equation 2,

D = 100(28.4/11.4)

D = 2491.23 kg/m³

Hence the density of the ceramic statue = 2491.23 kg/m³

7 0
3 years ago
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