Answer:
0.5 m/s²
Explanation:
Applying,
F = ma............... Equation 1
Where F = Force applied to the chair, m = mass of the student, a = acceleration of the chair
make a the subject of the equation
a = F/m............ Equation 2
From the question,
Given: F = 35 N, m = 70 kg
Substitute these values into equation 2
a = 35/70
a = 0.5 m/s²
Hence the new acceleration of the chair is 0.5 m/s²
Answer:
They experience the same magnitude impulse
Explanation:
We have a ping-pong ball colliding with a stationary bowling ball. According to the law of conservation of momentum, we have that the total momentum before and after the collision must be conserved:
where
is the initial momentum of the ping-poll ball
is the initial momentum of the bowling ball (which is zero, since the ball is stationary)
is the final momentum of the ping-poll ball
is the final momentum of the bowling ball
We can re-arrange the equation as follows
or
which means
(1)
so the magnitude of the change in momentum of the ping-pong ball is equal to the magnitude of the change in momentum of the bowling ball.
However, we also know that the magnitude of the impulse on an object is equal to the change of momentum of the object:
(2)
Therefore, (1)+(2) tells us that the ping-pong ball and the bowling ball experiences the same magnitude impulse:
The return stroke (the current that cause the visible flash) moves upward at a speed of about 320,000,000 ft per second or about 220,000,000 miles per hour (about 1/3 the speed of light).
The original vertical velocity = 0 (because the stone was dropped).
Assume that air resistance may be ignored.
Let x = the distance the stone drops in time t.
Then
x = 0*t + (1/2)*(9.8 m/s²)*(t s)²
= 4.9t² m
The height of the stone above ground is
h(t) = 900 - 4.9t² m
Answer: h(t) = 900 - 4.9t²
Answer:
As the car travels up the coaster it is gaining potential energy.
Explanation:
Because It has the greatest in amount of potential energy at the top of the coaster. when the car travels down the roller coaster it obtains speed and kinetic energy.
