The combined momentum of the passengers is 5000 kgm/s.
<h3>Combined momentum of the passenger</h3>
The combined momentum of the passengers is calculated as follows;
P = mv1 + mv2
where;
- m is mass of the passengers
- v1 is velocity of the first passenger
- v2 is velocity of the second passenger
P = m(v1 + v2)
P = 5000(-1 + 2)
P = 5000 kgm/s
Thus, the combined momentum of the passengers is 5000 kgm/s.
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Answer:
the two vehicles will be moving at a speed of 6.16 m/s
Explanation:
This is a case of completely inelastic collision, therefore, the conservation of momentum can be written as:
which given the information provided results into:
Total mechanical energy = kinetic energy + potential energy
E = KE + PE
E = ½mv² + mgh
E = ½(0.1 kg)(2 m/s)² + (0.1 kg)(9.8 m/s²)(1.5 m)
E = 0.2 J + 1.47 J
E = 1.67 J
Answer:
Explanation:
The center of mass lies on a line that joins position 4 of one start with position 4 of the other star. The shortest distance between these two points will produce the largest velocity. You are using F = m v^2/R
Small R = large force.
Large Force = increased speed.
The masses don't have any effect on the outcome: they remain constant.