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nadya68 [22]
4 years ago
12

Will the answer be B or D and why?

Mathematics
2 answers:
pogonyaev4 years ago
7 0
Hello.

The answer choice that is correct is answer choice "B.)"
Let's explain why.

For starters, our original image starts in the first quadrant of the graph. Our transformation is on the second quadrant. Let's take a look at our sharp edges of the first image: (4,2); (7,5); (3,7); and (2,4). If we were to turn it 90 degrees counterclockwise, we end up with our transformation image that has the sharp edges of (2,4); (5,7); (7,3); and (4,2). If you'd like to make this a more simple concept, put out your hand and turn it counterclockwise of 90 degrees and imagine your original image.

I hope this helps!
lisabon 2012 [21]4 years ago
3 0
It would be b. Idk that’s the answer my friend got
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Step-by-step explanation:

Step 1:

First, we must bring the equation to the form of ax^{2} +bx +c =0.

So -5 +2x^{2} = -6x becomes 2x^{2} +6x-5=0.

The value of a is the coefficient of the x^{2} term, the value of b is the coefficient of x term and c is the coefficient of the constant term.

Comparing the above equation to ax^{2} +bx +c =0, we get a = 2, b = 6, and c=-5.

We have the formula x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}.

Step 2:

By substituting the known values, we get

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a} =\frac{-6 \pm \sqrt{6^{2}-4 (2)(-5)}}{2 (2)}.

\frac{-6 \pm \sqrt{6^{2}-4 (2)(-5)}}{2 (2)} = \frac{-6 \pm \sqrt{36-4 (2)(-5)}}{4} .

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