The diagonal fencing will be the hypotenuse of a right triangle with sides 120yds long so:
h=√2(120^2))
h=√28800 yd
And the surrounding fencing will just be four times the side length of 120yds so:
s=480yd
So the total fencing needed is:
f=480+√28800 yards
f≈649.71 yd (to nearest hundredth of a yard) which is
f≈650 yds (to nearest whole yard)
But, I wasn't sure, if they just want the diagonal fencing needed then it is just:
f=√28800
f≈170 yds (to nearest yard)
Answer:
28
Step-by-step explanation:
2x-3y+z=-3 , x-5y+7z=-11 , -10x+4y-6z=28
X^2-5x+5x-25 (multiply (x-5) with (x+5))
X^2-25 ( -5x+5x =0)
Answer:
For a glider, which a paper airplane is the more lift the glider has the longer it can fly. However, you must keep the weight and drag in check to avoid flight failure.
Step-by-step explanation:
Answer:
<u>Using below system of inequalities</u>
<u>Following the rules </u>
- 1. Finding x- and y - intercepts
- 2. Connecting with dotted line for each as no equal symbol present in any inequality
- 3. Shade respective regions
- 4. Solution is the intersection of the shades regions
- 5. Select any three points in the solution region
<u>Line 1</u>
- y > 2x - 3
- x- intercept: y = 0 ⇒ 0 = 2x - 3 ⇒ 2x = 3 ⇒ x = 1.5
- y - intercept: x = 0 ⇒ y = -3
- Shaded region is above the line (or to the left)
<u>Line 2</u>
- y < x + 1
- x- intercept: y = 0 ⇒ 0 = x + 1 ⇒ x = -1
- y - intercept: x = 0 ⇒ y = 1
- Shaded region is below the line (or to the right)
<u>Selected points are:</u>