Simultaneous equations
Jamar=J
Josh=j
4J=j
20+J=2j
Then
4J=j
-4 (J)=-4(2j-20)
So
0=-7j+80
7j=80
j=80÷7
(5.59241)(10)^6 *Possible Answer*
I’m assuming you man degrees? Are these angles of a triangle?
This doesn’t really make sense because the angles in a triangle add up to 180° so your equation would be x+50+x+80+72=180
Combine like terms to get
2x+202=180
Then subtract 202 from both sides
2x=-22
So x would be -11 which doesn’t seem right lol
Answer:
£1443.89
Step-by-step explanation:
To start you take the £1700 and multiply it by 4% (or .04) to find how much it depreciates for the first year. For the first year the depreciation £68 so the next year it will be worth £1632 ( £1700 - 68). You do the same thing for the second year but you start with the amount its worth now (£1632) and multiply again by the 4%. The depreciation for the second year is 65.28. Now you take what it was worth at the start of the year (£1632) and subtract the depreciation for the second year (65.28) to get £1566.72. You do the same process again for the third year to end up with a value of £1504.05. Now for the 4th year you will take the value of £1504.05 and again multiply by the depreciation rate of 4% to find the last amount of depreciation which is £60.16. Take your starting value for year 4 (£1504.05) and subtract the amount of depreciation (£60.16) to get your answer of £1443.89.