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Ivan
3 years ago
6

Solve the formula for the specified variable. A=6P+4Prt for t

Mathematics
1 answer:
KatRina [158]3 years ago
6 0
Your answer will be t = -3P/2Pr + A/4Pr. :)
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3 years ago
What are the coordinates of the vertex of the function below write your answer in the form y-9= -6(x-1)^2
Oliga [24]

Answer:

The co-ordinates of the vertex of the function y-9= -6(x-1)^2 is (1, 9)

<u>Solution:</u>

Given, equation is y-9=-6(x-1)^{2}

We have to find the vertex of the given equation.

When we observe the equation, it is a parabolic equation,

We know that, general form of a parabolic equation is  y-9=-6(x-1)^{2}

Where, h and k are x, y co ordinates of the vertex of the parabola.

\text { Now, parabola equation is } y-9=-6(x-1)^{2} \rightarrow y=-6(x-1)^{2}+9

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7 0
3 years ago
I need help. <br><br> solve for k.<br> 881 = k - (-243)<br> k=?
DedPeter [7]

Answer:

638

Step-by-step explanation:

1. Isolate the variable 881 = k - (-243)

                                  -243         -243

2. combine like terms 881 - 243 = k

3. answer 638

5 0
3 years ago
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