What is the square root of 0 rounded to the nearest tenth?
2 answers:
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Answer:
a₆ = 13x + 31
Step-by-step explanation:
The nth term of an arithmetic sequence is
= a₁ + (n - 1)d
Here a₁ = 3x + 1 and d = 2x + 6 , then
a₆ = 3x + 1 + 5(2x + 6)
= 3x + 1 + 10x + 30
= 13x + 31