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Leno4ka [110]
3 years ago
12

What is a quartic function with only the two real zeros given?

Mathematics
1 answer:
serious [3.7K]3 years ago
4 0

Answer:

y = x^4 + 5x^3 + 5x^2 + 5x + 4

Step-by-step explanation:

Each of the latter three answers demonstrates one change of sign in its coefficients. According to Descarte's Rule of Signs, that means each of them has one positive real root. If there is a positive real root, the only two real roots will not be -4 and -1 (both negative).

The only viable option is the first one.

_____

There are other ways you can go at this. I like to let a graphing calculator show the zeros of functions of higher degree. Only the first function has only the two real roots given.

You can also evaluate each function or do synthetic division to see which polynomial has -1 or -4 as a root. Shown in the second attachment is the first function evaluated for x=-1.


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X/19 &lt; -7<br> Inqualities
Hitman42 [59]

Because 19 is being divided, you have to do the opposite. What's the opposite of division? Multiplication. So multiply 19 to -7, then get rid of the 19 on the x's side(cuz it was cancelled out). Now you should have x<-133. In case you don't know, positive times negative equals negative, but negative times negative equals positive.

---

hope it helps

6 0
3 years ago
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
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