What is a quartic function with only the two real zeros given?
1 answer:
Answer:
y = x^4 + 5x^3 + 5x^2 + 5x + 4
Step-by-step explanation:
Each of the latter three answers demonstrates one change of sign in its coefficients. According to Descarte's Rule of Signs, that means each of them has one positive real root. If there is a positive real root, the only two real roots will not be -4 and -1 (both negative).
The only viable option is the first one.
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There are other ways you can go at this. I like to let a graphing calculator show the zeros of functions of higher degree. Only the first function has only the two real roots given.
You can also evaluate each function or do synthetic division to see which polynomial has -1 or -4 as a root. Shown in the second attachment is the first function evaluated for x=-1.
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Interpreting the situation, it is found that Marjorie will have 240 left after paying her penalty.
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- When the piece lands on the red square, the penalty is equal to <u>30 times the sum they roll on two numbers.</u>
- Marjorie rolls 4 and 2, thus, the sum is 6.
- The penalty is of
- She currently has 420, the penalty removes 180, thus, she will have 420 - 180 = 240 left after paying her penalty.
A similar problem is given at brainly.com/question/12166019