Answer:
Step-by-step explanation:
B
its B
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We are asked to find the two integers, given that they are consecutive, and their sum is 65.

- Consecutive integers are right next to each other, like 12 and 13. or 65 and 66.
Let the first integer be x, and let the second integer be x+1.
Their sum is 65. Let's set up our equation:

Combine like terms:

Subtract 1 from both sides of the equal sign:

Divide both sides by 2:

To find the second integer, subtract the first integer from the sum of the two integers:


The integers are: 33 and 32.
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Step-by-step explanation:
The given inequality is :

Solving RHS of the inequality:

Adding 6 both sides of the inequality

The attached figure shows the graph for the given inequality.
Answer:
y = 3
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Step-by-step explanation:
<u>Step 1: Define</u>
y = 2x + 1
x = 1
<u>Step 2: Evaluate</u>
- Substitute in <em>x</em>: y = 2(1) + 1
- Multiply: y = 2 + 1
- Add: y = 3
Answer:
see explaination
Step-by-step explanation:
Using the formulla that
sum of terms number of terms sample mean -
Gives the sample mean as \mu=17.954
Now varaince is given by
s^2=\frac{1}{50-1}\sum_{i=1}^{49}(x_i-19.954)^2=9.97
and the standard deviation is s=\sqrt{9.97}=3.16
b) The standard error is given by
\frac{s}{\sqrt{n-1}}=\frac{3.16}{\sqrt{49}}=0.45
c) For the given data we have the least number in the sample is 12.0 and the greatest number in the sample is 24.1
Q_1=15.83, \mathrm{Median}=17.55 and Q_3=19.88
d) Since the interquartile range is Q_3-Q_1=19.88-15.83=4.05
Now the outlier is a number which is greater than 19.88+1.5(4.05)=25.96
or a number which is less than 15.83-1.5(4.05)=9.76
As there is no such number so the given sample has no outliers