Let's consider the equation;
7x+2=y <-- no denominator present
If you look at the graph, you will also notice that there are no possible values of x that cannot be represented through this graph. There will always be a corresponding y coordinate.
This can be applied to a wide range of equations where no denominator with an x value will have a vertical asymptote. Try to visualize a simpler situation with the same qualities if you don't know how to find the solution.
Hope I helped :)
Answer:
y=16
DC=276
Step-by-step explanation:
Since in a rectangle, the two opposite sides are always congruent (equal lengths), this means that 17y+4 is equal to the value of 11y+100.
So, solve for y.
17y+4=11y+100
-11y -11y
6y+4=100
-4 -4
<u>6y</u>=<u>96</u>
6 6
y=16
And then to find DC, you just need to plug in the y value.
11(16)+100=DC
176+100=DC
276=DC
Answer:
they have different areas and different perimeters
Answer:
a) 0.857
b) 0.571
c) 1
Step-by-step explanation:
18 juniors
10 seniors
6 female seniors
10-6 = 4 male seniors
12 junior males
18-12 = 6 junior female
6+6 = 12 female
4+12 = 16 male
A total of 28 students
The possibility of each union of events is obtained by summing the probabilities of the separated events and substracting the intersection. I will abbreviate female by F, junior by J, male by M, senior by S; So we have
P(J U F) = P(J) + P(F) - P(JF) = 18/28+12/28-6/28 = 24/28 = 0.857
P(S U F) = P(S) + P(F) - P(SF) = 10/28 + 12/28 - 6/28 = 16/28 = 0.571
P(J U S) = P(J) + P(S) - P(JS) = 18/28 + 10/28 - 0 = 1
Note that a student cant be Junior and Senior at the same time, so the probability of the combined event is 0. The probability of the union is 1 because every student is either Junior or Senior.
(Extra; but please give me brainliest
The sine of an angle in a right triangle is the ratio of the length of the opposite side to the length of the hypotenuse
If
<span>, then:
</span>opposite = a² - b²
hypotenuse = a² + b²
<span>By the Pythagorean theorem:
</span>
<span>So, the other trigonometric ratios:
</span>
<span>
</span>