Answer:
2.6
Step-by-step explanation:
Hope this helps:) Have a good day!
Hello!
If you want to find an equation that is parallel to another equation, and passing through the point (1, 4), you need to create a new equation with the same slope, you need to substitute the given point into the new equation to find the y-intercept.
m = 3, y = 3x + b (substitute the ordered pair)
4 = 3(1) + b (simplify)
4 = 3 + b (subtract 3 from both sides)
b = 1
Therefore, the line parallel to the line y = 3x - 2 and passing through the point (1, 4) is y = 3x + 1.
Well, if we see the graph of x^2
the vertex is (0,0)
if we reflect it acrosss the x axis, teh vertex is still (0,0)
verteical strech doesn't change the vertex
vertex of g(x) is same as f(x)
first answer
Answer:
0.0025 miles per second
Step-by-step explanation: