If it’s 30% converted to a decimal it’ll be .30
recalling that d = rt, distance = rate * time.
we know Hector is going at 12 mph, and he has already covered 18 miles, how long has he been biking already?

so Hector has been biking for those 18 miles for 3/2 of an hour, namely and hour and a half already.
then Wanda kicks in, rolling like a lightning at 16mph.
let's say the "meet" at the same distance "d" at "t" hours after Wanda entered, so that means that Wanda has been traveling for "t" hours, but Hector has been traveling for "t + (3/2)" because he had been biking before Wanda.
the distance both have travelled is the same "d" miles, reason why they "meet", same distance.
![\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ Hector&d&12&t+\frac{3}{2}\\[1em] Wanda&d&16&t \end{array}\qquad \implies \begin{cases} \boxed{d}=(12)\left( t+\frac{3}{2} \right)\\[1em] d=(16)(t) \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Blcccl%7D%20%26%5Cstackrel%7Bmiles%7D%7Bdistance%7D%26%5Cstackrel%7Bmph%7D%7Brate%7D%26%5Cstackrel%7Bhours%7D%7Btime%7D%5C%5C%20%5Ccline%7B2-4%7D%26%5C%5C%20Hector%26d%2612%26t%2B%5Cfrac%7B3%7D%7B2%7D%5C%5C%5B1em%5D%20Wanda%26d%2616%26t%20%5Cend%7Barray%7D%5Cqquad%20%5Cimplies%20%5Cbegin%7Bcases%7D%20%5Cboxed%7Bd%7D%3D%2812%29%5Cleft%28%20t%2B%5Cfrac%7B3%7D%7B2%7D%20%5Cright%29%5C%5C%5B1em%5D%20d%3D%2816%29%28t%29%20%5Cend%7Bcases%7D)

Answer:
10. 7
11. 4
12. 8
13. 7
14. 2
15. 3
16. 11
17. 9
18. 8
Step-by-step explanation:
Answer:
See below.
Step-by-step explanation:
1a)
<u>Angles:</u>
<u>Add:</u>
<u>Subtract:</u>
Angle a: 132.
1b)
To get angle h above 180°, <u>We need to add h + 164:</u>
h = 110.
This is how to get h over 180°.
Answer:

Step-by-step explanation:
Given

(a): Write as additive inverse.
An additive inverse is of the form a + (-b)
In this case:


So, the expression can be represented as:

(b): Number line representation
When the expression in (a) is solved.
The result is:

This means that the number line must accommodate 7 and -1.
Having said that, options (b) and (c) are out because their range is 0 to 15 and this excludes -1.
Option (d) is a wrong representation of 
Hence, (a) is correct