Ryan claims that any fraction located between 1/5 and 1/3 on a number line must have a denominator of 4. Enter a fraction that s
hows Ryan's Claim is incorrect.
1 answer:
let's firstly convert both fractions with the same denominator, by simply multiplying one by the denominator of the other, let's proceed,
![\bf \cfrac{1}{5}\cdot \cfrac{3}{3}\implies \cfrac{3}{15}~\hspace{7em}\cfrac{1}{3}\cdot \cfrac{5}{5}\implies \cfrac{5}{15} \\\\[-0.35em] ~\dotfill\\\\ \boxed{\cfrac{3}{15}}\rule[0.35em]{10em}{0.25pt}~~\cfrac{4}{15}~~\rule[0.35em]{10em}{0.25pt}\boxed{\cfrac{5}{15}}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B1%7D%7B5%7D%5Ccdot%20%5Ccfrac%7B3%7D%7B3%7D%5Cimplies%20%5Ccfrac%7B3%7D%7B15%7D~%5Chspace%7B7em%7D%5Ccfrac%7B1%7D%7B3%7D%5Ccdot%20%5Ccfrac%7B5%7D%7B5%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B15%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cboxed%7B%5Ccfrac%7B3%7D%7B15%7D%7D%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D~~%5Ccfrac%7B4%7D%7B15%7D~~%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%5Cboxed%7B%5Ccfrac%7B5%7D%7B15%7D%7D)
well, low and behold, 4/15 doesn't simplify further and is right between those two, and its denominator is not 4.
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