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Free_Kalibri [48]
3 years ago
15

Ryan claims that any fraction located between 1/5 and 1/3 on a number line must have a denominator of 4. Enter a fraction that s

hows Ryan's Claim is incorrect.
Mathematics
1 answer:
enyata [817]3 years ago
8 0

let's firstly convert both fractions with the same denominator, by simply multiplying one by the denominator of the other, let's proceed,

\bf \cfrac{1}{5}\cdot \cfrac{3}{3}\implies \cfrac{3}{15}~\hspace{7em}\cfrac{1}{3}\cdot \cfrac{5}{5}\implies \cfrac{5}{15} \\\\[-0.35em] ~\dotfill\\\\ \boxed{\cfrac{3}{15}}\rule[0.35em]{10em}{0.25pt}~~\cfrac{4}{15}~~\rule[0.35em]{10em}{0.25pt}\boxed{\cfrac{5}{15}}

well, low and behold, 4/15 doesn't simplify further and is right between those two, and its denominator is not 4.

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77julia77 [94]

D, while numbers is the answer

5 0
2 years ago
Multiply and give the answer in scientific notation: (2.3 x 10-3)(3 x 108)
bulgar [2K]
<span>(2.3 x 10^-3)(3 x 10^8)
=(</span>2.3 x 3)(10^-3 x 10^8)
= 6.9 x 10^5

hope it helps
6 0
3 years ago
Read 2 more answers
Jimmy buys 5 notebooks that each cost the same amount and 1 binder that costs $7.50. The total cost is $18.75. How much does eac
Varvara68 [4.7K]

Answer:

A. $2.25

Step-by-step explanation:

If you subtract $7.50 from $18.75 you get $11.25, then divide that by 5 and you'll get $2.25.

Hope this was useful.

3 0
2 years ago
Read 2 more answers
Prove that, in a right triangle with a 15° angle, the altitude to the hypotenuse is one fourth of the hypotenuse.
igomit [66]

Consider the attached figure. If AB has length 1, then BC has length sin(15°) and CD (the altitude of triangle ABC) has length sin(15°)·cos(15°).

By the double angle formula for sin(α), ...

... sin(2α) = 2sin(α)cos(α)

Rearranging, this gives

... sin(α)·cos(α) = sin(2α)/2

We have

... CD = sin(15°)·cos(15°) = sin(2·15°)/2

... CD = sin(30°)/2 = (1/2)/2 = 1/4

That is, the altitude, CD, is 1/4 the hypotenuse, AB, of triangle ABC.

3 0
3 years ago
Can someone answer this
GenaCL600 [577]
What is the question you just said Can someone answer this what's the question
4 0
3 years ago
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