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Anestetic [448]
3 years ago
13

How many solutions to y=2x-3 y=-x+3

Mathematics
2 answers:
Ivan3 years ago
8 0

Answer:

y = 1

Step-by-step explanation:

I dunno what you need but that's the answer to y...

frosja888 [35]3 years ago
6 0

Answer:

One solution, as there is only one intersection between these two lines.

x = 2, and y = 1 (point of interesection (2, 1) )

y = 2x-3

y = -x + 3

first step is to substitute the y of one equation into the other and solve for x.

- x + 3 = 2x - 3

___________

+x. +x

_____________

3 = 3x-3

_____________

+3 +3

____________

6 = 3x

_____________

÷3 ÷3

_______________

2 = x

______________

x = 2

_______________

We can verify this value is true by substituting it back into the equations and as a result also solving for the working y value.

x = 2 -> y = 2(x) - 3

2(2) - 3 = 4 - 3 = 1

y = 1

____________

x = 2 -> y = -(x) + 3

-(2) + 3 = -2 + 3 = 1

y = 1

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Artemon [7]
To solve the set of equations given above, we can use the substitution method where we substitute one equation to the other and solving for one variable. We do as follows:

<span>0.4x - 0.1y = 2
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6 0
3 years ago
Read 2 more answers
Joel is designing a ramp for a bike trick. He draws this diagram. What is the value of x?
inn [45]

Answer:

x = -1

x = 5

Step-by-step explanation:

Use pythagorean theorem: a² + b² = c²

x² + (2x + 2)² = (2x + 3)²

Since these are quantities, you'll have to make them into quadratic equations.

(2x + 2)(2x + 2) = 4x² + 4x + 4x + 4

(2x + 3)(2x + 3) = 4x² + 6x + 6x + 9

x² + 4x² + 4x + 4x + 4 = 4x² + 6x + 6x + 9

Combine like terms

5x² + 8x + 4 = 4x² + 12x + 9

Move one side to set the equation equal to 0

x² - 4x - 5 = 0

Solve

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<em>We</em><em> </em><em>can</em><em> </em><em>check</em><em> </em><em>that</em><em> </em><em>these</em><em> </em><em>are</em><em> </em><em>correct</em><em> </em><em>by</em><em> </em><em>plugging</em><em> </em><em>them</em><em> </em><em>in</em><em> </em><em>for</em><em> </em><em>x</em><em> </em><em>and</em><em> </em><em>seeing</em><em> </em><em>if</em><em> </em><em>they</em><em> </em><em>are</em><em> </em><em>equal</em>

<em>For</em><em> </em><em>example</em>

<em>(</em><em>-1</em><em>)</em><em>²</em><em> </em><em>+</em><em> </em><em>(</em><em>2</em><em>(</em><em>-1</em><em>)</em><em> </em><em>+</em><em> </em><em>2</em><em>)</em><em>²</em><em> </em><em>=</em><em> </em><em>(</em><em>2</em><em>(</em><em>-1</em><em>)</em><em> </em><em>+</em><em> </em><em>3</em><em>)</em><em>²</em>

<em>1</em><em> </em><em>=</em><em> </em><em>1</em>

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