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miskamm [114]
3 years ago
7

Performance scores are collected for 10 individuals and those scores are 17 12 20 11 8 18 17 9 12 and 15. Find where X sub i rep

resents the 10 scores.
Mathematics
1 answer:
Elden [556K]3 years ago
3 0

Step-by-step explanation:

x=10-20x567++dfggyjkkvd

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Thang decided to borrow ​$2000 from his local bank to help pay for a car. His loan was for 3 years at a simple interest rate of
Svetach [21]

Answer:

Thang will pay $300 as interest

Step-by-step explanation:

T = 3 years

P = $2000

R = 5%

Therefore

I = (2000 × 5 × 3)/100

I = 30000/100

I = $300

4 0
3 years ago
What is base number​
seropon [69]

Answer: Base numbers are the number of units, or numbers, we use in our counting system, also called a number system. The most common base number is ten because the digits 0-9 are used in the number system. In other words, whenever we want to tell a number to someone we don't use any numbers besides 0-9. If it was a base-5 number system we would only use five different digits, like 0-4.

Step-by-step explanation:

7 0
3 years ago
The number of tourists visiting a city doubles every month during the two-month period beginning in Jan, 1st and ending
GrogVix [38]

Answer:

2x

Step-by-step explanation:

4 0
3 years ago
Draw out a two column proof for each problem below. Complete all problems on one page and upload ONE photo of the entire assignm
Hunter-Best [27]

Two or more <u>triangles</u> are <em>congruent </em>if on comparison, they have equal lengths of <u>sides,</u> and measure of <u>angles</u>.

Therefore, the required proofs for each question are shown below:

Problem 1:

<em>Congruent triangles</em> are <u>triangles</u> with equal lengths of <em>corresponding</em> <u>sides</u> and measures of internal <u>angles</u>.

Thus,

                     STATEMENT                          REASON

1. <NMQ ≅ <NPQ                            Any point on a <em>perpendicular bisector</em>      

                                                        makes <u>equal</u> measure of angle with the

                                                        two ends of the<em> line</em> segment.

2. NQ ⊥ MP                                     Definition of a<u> line</u>.

3. MQ ≅ PQ                                     <em>Equal segments</em> of a bisected <u>line</u>.

4. MN ≅ PN                                     Any point on a <em>perpendicular bisector </em>    

                                                        is at the same <u>distance</u> to the

                                                        two ends of the <em>line segment</em>.

5. <MNQ ≅ <PNQ                           <u>Equal</u> measure of the <u>bisected</u> angle.

Problem 2:

A line <em>segment</em> is the shortest <u>distance</u> between two points.

            STATEMENTS                    REASONS

1. m<PSR  ≅ m<PSQ                A <em>perpendicular bisector </em>is always at a right  

                                                  angle to the <u>bisected</u> <em>line segment</em>.

2. m<RPS ≅ m<QPS                 Equal measure of the <u>bisected</u> <em>angle</em>.

3. RS ≅ QS                                Property of a <u>bisected</u> <em>line</em> segment.

4. PR ≅ PQ                                Any point on a <em>perpendicular bisector </em>    

                                                  is at the same <u>distance</u> to the two ends of  

                                                 the <u>line</u> segment.

For more clarifications on the perpendicular bisector of a line segment, visit: brainly.com/question/12475568

#SPJ1

3 0
2 years ago
I need help figuring out what I did wrong
rewona [7]

Answer:

D

Step-by-step explanation:

Using the addition formula for sine

sin(a + b) = sinacosb + cosasinb

and the exact values

sin(\frac{\pi }{4} ) = cos(\frac{\pi }{4} ) = \frac{\sqrt{2} }{2} , cos(\frac{\pi }{6}) = \frac{\sqrt{3} }{2} , sin(\frac{\pi }{6}) = \frac{1}{2}

Note that \frac{5\pi }{12} = \frac{\pi }{4} + \frac{\pi }{6} , thus

sin(\frac{5\pi }{12})

= sin(\frac{\pi }{4} + \frac{\pi }{6} )

= sin(\frac{\pi }{4})cos(\frac{\pi }{6} ) + cos(\frac{\pi }{4})sin(\frac{\pi }{6})

= ( \frac{\sqrt{2} }{2} × \frac{\sqrt{3} }{2} ) + ( \frac{\sqrt{2} }{2} × \frac{1}{2} )

= \frac{\sqrt{6} }{4} + \frac{\sqrt{2} }{4}

= \frac{\sqrt{6}+\sqrt{2}  }{4} → D

4 0
3 years ago
Read 2 more answers
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