Answer:
y=-3x-5
Step-by-step explanation:
the picture below is how i did it
Answer:
Option D is the correct option.
<em>please </em><em>see</em><em> the</em><em> attached</em><em> picture</em><em> for</em><em> full</em><em> solution</em><em>.</em><em>.</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>
<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em>
Answer:
It increases
Step-by-step explanation:
PLZZ mark brainliest!!!
Answer:
Both air balloon and water balloon data are best modeled by an exponential function.
Step-by-step explanation:
Air balloon
Time (seconds) Volume (cubic centimeters)
0 95
3 69
6 50
9 37
12 27
The relation Volume variation/time is constant for lines, In this case, this value change from point to point, as can be seen next.
(69 - 95)/3 = -8.67
(50 - 69)/3 = -6.33
(37 - 50)/3 = -4.33
(27 - 37)/3 = -3.33
Water balloon
Time (seconds) Volume (cubic centimeters)
0 30
3 15.8
6 7.8
9 4
12 2
(30 - 15.8)/-3 = -4.73
(15.8 - 7.8)/-3 = -2.67
(7.8 - 4)/-3 = -1.27
(4 - 2)/-3 = -0.67
In this case, the relation Volume variation/time also change from point to point.
Then, both air balloon and water balloon data are best modeled by an exponential function.
It’s D
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