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2 years ago

6

9x1,000 3rd grade mental math

2 answers:

tekilochka [14]2 years ago

8 0

To multiply factors of 10 (that's anything with zero on the end) just multiply the numbers that are NOT zeros on the end and then add the zeros back onto the answer. For example..

500 × 3
multiply 5 × 3 = 15 then add the 2 zeros back 1,500.

Your problem is 9 × 1000
9 × 1 = 9
add the three zeros back
9,000.

german2 years ago

5 0

Answer:

9000

Step-by-step explanation:

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Andre45 [30]

Answer:

The consecutive odd integers are (15, 17, 19) or (-17, -15, -13).

Step-by-step explanation:

Let the three consecutive odd integers be: $x-2,x\ and \ x+2$

The condition given is:

$4[x-2+x+x+2]=3x(x+2)-765$

Solve this for <em>x</em> as follows:

$4[x-2+x+x+2]=3x(x+2)-765\\4\times 3x=3x^{2}+6x-765\\3x^{2}-6x-765=0\\x^{2}-2x-255=0\\x^{2}-17x+15x-255=0\\x(x-17)+15(x-17)=0\\(x-17)(x+15)=0$

If $(x-17)=0$ then the value of <em>x</em> is 17.

The odd numbers are:

$x-2=17-2=15\\x=17\\x+2=17+2=19$

If $(x+15)=0$ then the value of <em>x</em> is -15.

The odd numbers are:

$x-2=-15-2=-17\\x=-15\\x+2=-15+2=-13$

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