Net force is
1 answer:
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a) ,
The work done by the student in each trial is equal to the gravitational potential energy gained by the student:
where
m = 68 kg is the mass of the student
g = 9.8 m/s^2 is the acceleration of gravity
is the gain in height of the student
For the first student, , so the work done is
The second student runs up to the same height (3.5 m), so the work done by the second student is the same:
2) ,
The power exerted by each student is given by
where
W is the work done
t is the time taken
For the first student, and
, so the power exerted is
For the second student, and
, so the power exerted is