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Andre45 [30]
3 years ago
14

What is the speed of a car that travels 150 km in 3.00 hrs?

Physics
2 answers:
zhuklara [117]3 years ago
4 0
You would do distance divided by speed. So 150÷3, which would equal 5km per hour.
nalin [4]3 years ago
3 0
5km per hour. Hope this helps!
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Which atomic number is the threshold value below which fusion may occur?
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Answer:

The atomic number 26(iron) is the threshold value below which the fusion might occur.

Explanation:

Nuclear fusion is a reaction in which two or more nuclei are combined to form one or more different atomic nuclei and subatomic particles.

Energy released in a fusion reaction is because of a key feature of nuclear matter called the binding energy which is a measure of the efficiency with which its constituent nucleons are bound together.

As we go up in atomic number, the energy released per nuclei goes down until it hits a minimum which is for atomic number 26 (iron) and fusion is not possible.

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Answer:the first one was x

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7. A 1.0 kg metal head of a geology hammer strikes a solid rock with a velocity of 5.0 m/s. Assuming all the energy is retained
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The increase in temperature of the metal hammer is 0.028 ⁰C.

The given parameters:

  • <em>mass of the metal hammer, m = 1.0 kg</em>
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The increase in temperature of the metal hammer is calculated as follows;

Q = K.E\\\\mc \Delta T = \frac{1}{2}  mv^2\\\\\Delta T = \frac{v^2}{2 c}

where;

<em>c is the </em><em>specific heat capacity</em><em> of the metal hammer</em>

<em />

Assuming the metal hammer is iron, c = 450 J/kg⁰C

\Delta T = \frac{5^2}{2 \times 450} \\\\\Delta T = 0.028 \ ^0C

Thus, the increase in temperature of the metal hammer is 0.028 ⁰C.

Learn more about heat capacity here: brainly.com/question/16559442

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Answer:

The answer is below

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Centripetal acceleration is given by the formula:

a = v² / r; where v is the speed of the object and r is the radius of curvature (distance from object ot the center of circle).

Let us assume the car has a velocity of v m/s. For the curve with radius of curvature r:

a₁ = v² / r

For the curve with radius of curvature r = 2r:

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Therefore the centripetal acceleration is greater in the curve with radius pf curvature r and smaller in the curve with twice the radius of curvature of the other.

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