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3 years ago

F(x+h) - f(x) over h. Find and simplify

Mathematics

1 answer:

solong [7]3 years ago

6 0

What does f(x) equals

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If f(x) = 1/9x-2, what is f^-1(x)?

gavmur [86]

Answer:

9x-2

Step-by-step explanation:

f^-1(x)=1/f(x)=9x-2

8 0

2 years ago

A triangle with a base of 10 units and height of 8 units. Find the area of the triangle. The area of the triangle is square unit

Semmy [17]

The area is 40 units

6 0

2 years ago

Read 2 more answers

Present Value Hoew much shuold be deposited in an account paying 7.2% interest compounded monthly in order to have a balance of

jonny [76]

Answer:$6451.6 should be deposited.

Step-by-step explanation:

The principal was compounded monthly. This means that it was compounded 12 times in a year. So

n = 12

The rate at which the principal was compounded is 7.2%. So

r = 7.2/100 = 0.072

It was compounded for 3 years. So

t = 3

The formula for compound interest is

A = P(1+r/n)^nt

A = total amount in the account at the end of t years. A is given as $8000 Therefore,

8000 = P (1+0.072/12)^12×3

8000 = P(1+0.006)^36

8000 = P(1.006)^36

P = 8000/1.24

P = $6451.6

6 0

3 years ago

Integrate 1 - x / x(x2 + 1) d x by partial fractions.

solniwko [45]

Answer:

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

Step-by-step explanation:

step 1:- by using partial fractions

$[tex]\frac{1-x}{x(x^{2}+1) } =\frac{A(x^{2}+1)+(Bx+C)(x }{x(x^{2}+1) }$ ......(1)

step 2:-

solving on both sides

$1-x=A(x^{2} +1)+(Bx+C)x......(2)$

substitute x =0 value in equation (2)

1=A(1)+0

A=1

comparing x^2 co-efficient on both sides (in equation 2)

0 = A+B

0 = 1+B

B=-1

comparing x co-efficient on both sides (in equation 2)

-1 = C

step 3:-

substitute A,B,C values in equation (1)

now

$\\\int\limits^ {} \, \frac{1-x}{x(x^{2}+1) } d x =\int\limits^ {} \frac{1}{x} d x +\int\limits^ {} \frac{-x}{x^{2}+1 } d x -\int\limits \frac{1}{x^{2}+1 } d x$

by using integration formulas

i) by using $\int\limits \frac{1}{x} d x =log x+c........(a)\\\int\limits \frac{f^{1}(x) }{f(x)} d x= log(f(x)+c\\$ .....(b)

$\int\limits tan^{-1}x dx =\frac{1}{1+x^{2} } +C$ .....(c)

step 4:-

by using above integration formulas (a,b,and c)

we get answer is

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

6 0

3 years ago

2. What is the slope passing through the points (2, -1) and (-4, 11)

algol [13]

Answer:

I believe it is y equals 3 minus 2x.

4 0

2 years ago