All categories

3 years ago

One of the following sterilization method is different from the other and why?

Biology

1 answer:

katen-ka-za [31]3 years ago

5 0

Answer:

The correct answer is D) Pasteurization.

Explanation:

Pasteurization is different from the others because It doesn't have a whole lot to do with heat.

Hope this helps! :)

(I'm pretty sure this is the correct answer but sorry in advance if it isn't.)

:) :) :) :) :) :) :)

You might be interested in

Mendel’s law of independent assortment states that alleles of genes on nonhomologous chromosomes assort independently during gam

Lera25 [3.4K]

The mix of alleles from various genes that end up in the daughter cells is determined by the anaphase 1 of meiosis 1.

Chromosome segregation during meiosis is mirrored in the segregation of alleles. During anaphase, 1 of meiosis 1 homologous chromosomal separation leads to allele segregation.

Chromosomes display autonomous assortment when they are randomly split into daughter cells during meiosis.

<h3>What takes place in anaphase 1?</h3>

During meiosis I, sister chromatids remain together as homologous chromosomes separate. To appreciate the development of germ cells, it is crucial to comprehend how this odd chromosomal segregation behavior came to be. Here, we show that the pattern of chromosomal segregation during meiosis I is determined by the microtubule-kinetochore interactions that are inhibited during prophase I and the premeiotic S phase.

To know more about allele segregation visit:

brainly.com/question/2193571

#SPJ4

7 0

1 year ago

One of the stages of the cell cycle is mitosis, involving

Arada [10]

the answer is C, the division of one cell into two identical cells :3

5 0

3 years ago

Cystic fibrosis (CF) is one of most common recessive disorders among Caucasians it affects 1 in 1,700 newborns. What is the expe

Phantasy [73]

Answer: The expected frequency of carriers is P(Aa)=0.046.

The proportion of childs with CF is P(aa)=0.024.

25% of having a child with CF (aa).

Explanation:

Hardy-Weinberg's principle states that in a large enough population, in which mating occurs randomly and which is not subject to mutation, selection or migration, gene and genotype frequencies remain constant from one generation to the next one, once a state of equilibrium has been reached which in autosomal loci is reached after one generation. So, a population is said to be in balance when the alleles in polymorphic systems maintain their frequency in the population over generations.

Given the gene allele frequencies in the gene pool of a population, it is possible to calculate the expected frequencies of the progeny's genotypes and phenotypes. <u>If P = percentage of the allele A (dominant) and q = percentage of the allele a (recessive)</u>, the checkerboard method can be used to produce all possible random combinations of these gametes.

Note that p + q = 1, that is, the percentages of gametes A and a must equal 100% to include all gametes in the gene pool.

The genotypic frequencies added together should also equal 1 or 100%, and all the equations can be summarized as follows:

$p+q=1\\(p+q)^{2} = p^{2} +2pq+q^{2} = 1\\P(AA)=p^{2} \\P(aa)=q^{2} \\P(Aa)=2pq1$

So, there are 1700 individuals and only one is affected. Since it is a recessive disorder, the genotype of that individual must be aa. So the genotypic frequency of aa is 1/1700=0.000588.

Then, $P(aa)=q^{2}=0.000588$ . And with that we can calculate the value of q,

$P(a)=q=\sqrt{0.000588}=0.024$

And since we know that p+q=1, we can find out the value of p.

$p+0.024=1\\1-0.024=p\\p=0.976$

Next, we find out the genotypic frequency of the genotype AA:

$P(A)=p=0.976\\P(AA)=p^{2} = 0.976^{2}=0.95$

Now, we can find out the genotypic frequency of the genotype Aa:

$P(Aa)=2pq=2 x 0.976 x 0.024 = 0.046$

Notice than:

$p^{2} + 2pq + q^{2} = 1\\x^{2} 0.976^{2} + 2 x 0.976 x 0.024 + 0.024^{2} = 1$

Then, the expected frequency of carriers is P(Aa)=0.046

The proportion of childs with CF is P(aa)=0.024

If two parents are carriers, then their genotypes are Aa.

Gametes produced by them can only have one allele of the gene. So they can either produce A gametes, or a gametes.

In the punnett square, we can see that there genotypic ratio is 2:1:1 and the phenotypic ratio is 3:1. So, there is a probability of 25% of having an unaffected child, with both normal alleles (AA); 50% of having a carrier child (Aa) and 25% (0.25) of having a child with CF (aa).

5 0

4 years ago

During translation, the peptide bond formation is catalyzed by:.

Dafna11 [192]

Answer:

RNA (referred to as a ribozyme)

Explanation:

7 0

2 years ago

In sickle-cell disease, as a result of a single amino acid change, the hemoglobin tetramers associate with each other and assemb

Phoenix [80]

Answer:

One of the common genetic disorders is sickle cell anemia, in which 2 recessive alleles must meet to allow for destruction and alteration in the morphology of red blood cells. This usually leads to loss of proper binding of oxygen to hemoglobin and curved, sickle-shaped erythrocytes. The mutation causing this disease occurs in the 6th codon of the HBB gene encoding the hemoglobin subunit β (β-globin), a protein, serving as an integral part of the adult hemoglobin A (HbA), which is a heterotetramer of 2 α chains and 2 β chains that is responsible for binding to the oxygen in the blood. This mutation changes a charged glutamic acid to a hydrophobic valine residue and disrupts the tertiary structure and stability of the hemoglobin molecule. Since in the field of protein intrinsic disorder, charged and polar residues are typically considered as disorder promoting, in opposite to the order-promoting non-polar hydrophobic residues, in this study we attempted to answer a question if intrinsic disorder might have a role in the pathogenesis of sickle cell anemia. To this end, several disorder predictors were utilized to evaluate the presence of intrinsically disordered regions in all subunits of human hemoglobin: α, β, δ, ε, ζ, γ1, and γ2. Then, structural analysis was completed by using the SWISS-MODEL Repository to visualize the outputs of the disorder predictors. Finally, Uniprot STRING and D2P2 were used to determine biochemical interactome and protein partners for each hemoglobin subunit along with analyzing their posttranslational modifications. All these properties were used to determine any differences between the 6 different types of subunits of hemoglobin and to correlate the mutation leading to sickle cell anemia with intrinsic disorder propensity.

Explanation:

7 0

4 years ago