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4 years ago

9

jason is a salesperson in the eclectionics department of a store. he is 16% short of his goal for the week. his goal for the wee

k is to ear $550. For each CD he sells, he earsns $44. how many CD players does he need to sell for him to make his goal

1 answer:

Orlov [11]4 years ago

5 0

I think you do 550 x .16(16%)=88 and each CD sells for 44 so 88/44

Answer= He needs to sell 2 CD's

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You buy Apple stock for $120 per share over a period of time the stock value increased at a weekly rate of 5% you sell the stock

Rainbow [258]

Answer:

8.31 weeks

Step-by-step explanation:

Given that the cost of one share of Apple stock, C=$120

Rate is the increment of the stock value, R= 5%/week=0.05 / week.

Assuming that after t week, the stock has been sold for $180.

Since the stock value increased at 5% every week, so, the interest is compounded weekly, so

$S=C\left(1+R\right)^t \\\\ \Rightarrow 180 = 120\left(1+0.05\right)^t \\\\ \Rightarrow 180 = 120\left(1.05 )^t \\\\$

$\Rightarrow \frac{180}{120}=1.05^t \\\\\Rightarrow 1.5=1.05^t$

$\Rightarrow \ln(1.5)=t \ln(1.05)$ [taking log both sides]

$\Rightarrow t=\frac {\ln(1.5)}{\ln(1.05)}=8.31$ weeks

Hence, after 8.31 weeks the stock has been sold for $180.

6 0

3 years ago

Going back to bed now ill answer questions at 6:00 am. Its only 3:18 am.

Olegator [25]

Can you help me with my question please?

7 0

3 years ago

Read 2 more answers

If f x equals x -3 + g x equals 1 - x 2 - 9 find ( f og) (x and give any restrictions on its domain

evablogger [386]

$\begin{gathered} f(x)=x-3 \\ g(x)=\frac{1}{x^2-9} \\ (\text{fog)(x)}=\frac{1}{x^2-9}-3 \end{gathered}$

the denominator cannot be zero, because the division by zero is not defined, therefore:

$\begin{gathered} x^2-9=0 \\ \text{Solving for x:} \\ x^2=9 \\ \sqrt[]{x^2}=\sqrt[]{9} \\ x=\pm3 \end{gathered}$

Therefore the domain of (f o g)(x) is:

$D\colon(-\infty,-3)\cup(-3,3)\cup(3,\infty)$

3 0

1 year ago

What is the value of this expression when c = -4 and d = 10?

Airida [17]

What is the expression

4 0

2 years ago

The rectangular coordinates of a point are given. Find the polar coordinates (r,theta) of this point with theta expressed in r

alexandr402 [8]

Answer:}

In polar coordinates P is

P ( 12 ; 2.618 )

Step-by-step explanation:

The point (ectangular coordinates)

P ( -6√3 ; 6 ) P ( x ; y )

Polar coordinates P ( r ; θ )

x = r cos θ

y = r sin θ r > 0 and 0 ≤ θ ≤ 2π

Then

r = √ (x)² + (y)² r = √(36)²*3 +( 36)² r = √144

r = 12 (hypothenuse module always positive)

The point P ( -6√3 ; 6 ) is in second cuadrant between 90° and 180°

angle between r and horizontal axis x is equal to θ

tan α = l.opp/ l.adj. tan θ = y/x tan θ = - 6 /6√3

tan α = - 1/√3

Then α = 180⁰ - 150⁰ = 30⁰ or θ = 150⁰

to express that value in radians we have :

1 π radian = 180⁰ ⇒ 3,1416 radians = 180⁰

x ?? = 150⁰

x = radians

Finally the point is P ( 12 ; 2.618 )

6 0

3 years ago