4x-3+7x+1
Ones with a variable: 4 & 7
Only whole number: -3 & 1
The answer is option two: -3 and 1; 4x and 7x
Let x gallons be the amount of pure antifreeze that should be added to the 30% solution to produce a solution that is 65% antifreeze. Then the total amount of antifreeze solution will be x+3 gallons.
There are 30% of pure antifreeze in 3 gallons of solution, then
3 gallons - 100%,
a gallons - 30%,
where a gallons is the amount of pure antifreeze in given solution.
Mathematically,
Now in new solution there will be x+0.9 gallons of pure antefreeze.
x+3 gallons - 100%,
x+0.9 - 65%
or
Answer: he should add 3 gallons of pure antifreeze.
If you would like to solve 2x + 5y = - 13 and 3x - 4y = -8, you can do this using the following steps:
<span>2x + 5y = -13 /*4
3x - 4y = -8 /*5
</span>_________________
8x + 20y = -52
15x - 20y = -40
_________________
8x + 15x + 20y - 20y = -52 - 40
23x = -92 /23
x = -92 / 23
x = -4
<span>2x + 5y = -13
</span>2 * (-4) + 5y = -13
-8 + 5y = -13
5y = -13 + 8
5y = -5
y = -1
(x, y) = (-4, -1)
The correct result would be D.) <span>(-4, -1).</span>
1) A(-5,-3); B(-6,-1); C(-3,-1) ; D(-2,-3)
When a refection is done about x-axis, the values of the abscise x remain identical & the value of ordinate just change their signs:
A(-5,-3); A'(-5,+3)
B(-6,-1); B'(-6,+1)
C(-3,-1); C'(-3,+1)
D(-2,-3); D'(-2,+3)
2) A'B'C'D' is translated 3 UNITS RIGHT, that means the ordinated of A'B'C'D'
are the same but the abscises have been increased by 3 UNITS ;
A'(-5,+3) ==>A"(-2,3)
B'(-6,+1) ==>B"(-3,1)
C'(-3,+1) ==>C"(0,1)
D'(-2,+3) ==>D"(1,3)
