Suppose a researcher is interested in understanding the variation in the price of store brand milk. a random sample of 36 grocer
1 answer:
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Part (a)
The domain is the set of allowed x inputs of a function.
The graph shows that x = 0 is not allowed because of the vertical asymptote located here. It seems like any other x value is fine though.
<h3>Domain: set of all real numbers butTo write this in interval notation, we can say which is the result of poking a hole at 0 on the real number line.
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The range deals with the y values. The graph makes it seem like it stretches on forever in both up and down directions. If this is the case, then the range is the set of all real numbers.
<h3>Range: Set of all real numbers</h3>In interval notation, we would say which is almost identical to the interval notation of the domain, except this time of course we aren't poking at hole at 0.
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Part (b)
<h3>The x intercepts are x = -4 and x = 4</h3>We can compact that to the notation
These are the locations where the blue hyperbolic curve crosses the x axis.
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Part (c)
<h3>Answer: There aren't any horizontal asymptotes in this graph.</h3>Reason: The presence of an oblique asymptote cancels out any potential for a horizontal asymptote.
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Part (d)
The vertical asymptote is located at x = 0, so the equation of the vertical asymptote is naturally x = 0. Every point on the vertical dashed line has an x coordinate of zero. The y coordinate can be anything you want.
<h3>Answer: x = 0 is the vertical asymptote</h3>=======================================================
Part (e)
The oblique or slant asymptote is the diagonal dashed line.
It goes through (0,0) and (2,6)
The equation of the line through those points is y = 3x
If you were to zoom out on the graph (if possible), then you should notice the branches of the hyperbola stretch forever upward but they slowly should approach the "fencing" that is y = 3x. The same goes for the vertical asymptote as well of course.
<h3>Answer: Oblique asymptote is y = 3x</h3>Answer:
There is one extraneous solution at
The only solution is
Step-by-step explanation:
Given:
The equation to solve is given as:
In order to solve, we will first isolate the radical part.
<em>Adding -5 on both the sides, we get:</em>
<em>Now, squaring both the sides, we get:</em>
Now, let us check whether the calculated values satisfy the equations or not.
Plug in 4 and 7 for 'x' and check the value of the equation.
At ,
But, 6 is not equal to 4 and hence 4 is not a solution to the given equation. It is an extraneous solution for the given equation.
Now, at
Therefore, is a solution to the equation.
Hence, there is one extraneous solution at
The only solution is