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ankoles [38]
2 years ago
10

Math help!!! Can somebody answer 1&2.

Mathematics
1 answer:
gregori [183]2 years ago
3 0

Answer:

1) MON 2) MPO

Step-by-step explanation:

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A building casts a 17-foot shadow. A 6-foot man standing next to the building casts a 2.5-foot shadow. What is the height, in fe
masha68 [24]
So the way you would find it is a ratio. 

1. \frac{6}{2.5}     \frac{x}{17}
2. =(6)(17)/(2.5)
3. =102/2.5
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7 0
3 years ago
A particle is moving along the curve y= 4sqrt(5x+11) . As the particle passes through the point (5,24) , its -coordinate increas
kupik [55]

The rate of change of the distance from the particle to the origin at this instant is 3 units per second.

<h3>What is the rate of change?</h3>

The instantaneous rate of change is the rate of change at a particular instant.

A particle is moving along the curve

y= 4\sqrt{5x+11} .

The rate of change of y is given as:

dy / dx = 2

by differentiating both sides,

\dfrac{dy}{dx} = 4\dfrac{1}{2\sqrt{5x+11} }  5\dfrac{dx}{dt} \\\\\dfrac{dy}{dx} = \dfrac{10}{\sqrt{5x+11} }\dfrac{dx}{dt}\\\\

From the question, we have:

(x, y) =  (5,24)

Substitute 5 for x and dy / dx = 2

\dfrac{dy}{dx} = \dfrac{10}{\sqrt{5x+11} }\dfrac{dx}{dt}\\\\\\5= \dfrac{10}{\sqrt{5(5)+11} }\dfrac{dx}{dt}\\\\\\\sqrt{5(5)+11} = 2\dfrac{dx}{dt}\\\\\\\dfrac{dx}{dt} = 6/ 2 = 3

Hence, the rate of change of the distance from the particle to the origin at this instant is 3 units per second.

Read more about rates of change at:

brainly.com/question/13103052

#SPJ1

8 0
1 year ago
Please help me is for my homework​
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I hope this help you

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3 years ago
What is x if 5x = 30?
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So 5x=30
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so the answer is last one !
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