If m<mkl=83. m<jkl=127. and m<jkm=(9x-10). find the value of x
1 answer:
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Answer:
x = - 7, x = 1
Step-by-step explanation:
Given
x² + 6x = 7
To complete the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(3)x + 9 = 7 + 9
(x + 3)² = 16 ( take the square root of both sides )
x + 3 = ± = ± 4 ( subtract 3 from both sides )
x = - 3 ± 4
x = - 3 - 4 = - 7
x = - 3 + 4 = 1
Solution set = { - 7, 1 }