<span>6x^2y + 8x^2 − 30y − 40
= 2x^2(3y + 4) - 10(3y + 4)
= (2x^2 - 10)(3y + 4)
= 2(x^2 - 5)(3y + 4)</span>
Since the 6 is in the hundreds place and it is above 5, then you round the thousands place up one to 88000
Answer:
Conclusion:
Step-by-step explanation:
Given
We know that the diagonals of a parallelogram bisect each other.
Therefore,
Given RT = x and TP = 5x-28, so
x = 5x-28
5x = x+28
5x-x = 28
4x = 28
divide boh sides by 4
4x/4 = 28/4
x = 7
Thus, the value of x = 7
Similarly,
QT = TS
Given QT = 5y and TS = 2y+12, so
5y = 2y+12
5y-2y = 12
3y = 12
divide both sides by 3
3y/3 = 12/3
y = 4
Thus, the value of y = 4
Conclusion:
Answer:
Lots of "ifs" here.
A=bh/2 is the formula for the area of a triangle.
A=bh is the formula for the area of a rectangle or a parallelogram.
If the 6 & 4 area the base & height of a rectangle, then (6)(4) = 24 in^2
If the 6 & 10 are the base and height of a triangle, then 1/2(6)(10) = 30 in^2
Step-by-step explanation:
