A dilation has center (0, 0). Find the image of each point for the given scale factor.

Mathematics

2 answers:

zhenek [66]3 years ago

7 0

Here the centre of dilation is (0,0) and the point is (3,4) and the scale factor is 7 .

To find the image after the dilation, we need to multiply each coordinate by the scale factor that is 7 . And on multiplying we will get, 3 times 7=21 and 4 times 7=28.

THerefore the point that we get after dilation is (21,28) .

Kay [80]3 years ago

7 0

Answer:

(21, 28)

Step-by-step explanation:

Multiply 3 x 7 which equals 21 and 4 x 7 which equals 28.

You might be interested in

Need some help asap thanks!

Alex Ar [27]

Angle W is 125 degrees since the two have to add up to 360, since they form a whole, round angle.
Angle Y is 138 degrees, since the two angles there form a straight line, making a total of 180, then subtracting 42 to find y.
Angle X is 50 degrees, since in the diagram, it shows that the two angles form a right angle, giving it a total of 90 degrees. Then all you have to do is subtract 40.
Now, for Angle Z, you have to add up all the angles you know in shape B, which is 125+138+40=303. Now, since all quadrilaterals interior angles add up to 360 degrees, you do 360-303=57. So, Angle Z =57

3 0

3 years ago

What is the value of 6P6? A.1 B.36 C.720 D.46,656

3241004551 [841]

$the\ permutationon:\ \ n\ P\ x= \frac{n!}{(n-x)!} \\ \\6\ P\ 6= \frac{6!}{(6-6)!} = \frac{6!}{0!}= \frac{2\cdot3\cdot4\cdot5\cdot6}{1}=720$

$Ans.\ C$

3 0

3 years ago

Express using a radical

wlad13 [49]

Answer $\sqrt[4]{6}$ $\sqrt[4]{b^3}$ $\sqrt[4]{c}$