Answer:
The values of and
for a linear system with infinitely many solutions are -2 and 5, respectively.
Step-by-step explanation:
Let , if this linear system has infinitely many solutions, then the following conditions must be met:
and
.
and
The values of and
for a linear system with infinitely many solutions are -2 and 5, respectively.
Answer:
The probability of one or more catastrophes in:
(1) Two mission is 0.0166.
(2) Five mission is 0.0410.
(3) Ten mission is 0.0803.
(4) Fifty mission is 0.3419.
Step-by-step explanation:
Let <em>X</em> = number of catastrophes in the missions.
The probability of a catastrophe in a mission is, P (X) = .
The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.
The probability mass function of <em>X </em>is:
In this case we need to compute the probability of 1 or more than 1 catastrophes in <em>n</em> missions.
Then the value of P (X ≥ 1) is:
P (X ≥ 1) = 1 - P (X < 1)
= 1 - P (X = 0)
(1)
Compute the compute the probability of 1 or more than 1 catastrophes in 2 missions as follows:
(2)
Compute the compute the probability of 1 or more than 1 catastrophes in 5 missions as follows:
(3)
Compute the compute the probability of 1 or more than 1 catastrophes in 10 missions as follows:
(4)
Compute the compute the probability of 1 or more than 1 catastrophes in 50 missions as follows: