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velikii [3]
2 years ago
8

There are no universally accepted definitions of the ages of Millennials and Generation Xers; the consensus is that the former a

re Americans born between 1984 and 2000 and the latter are Americans born between 1965 and 1984. Baby boomers are defined as people born between 1946 and 1964. An analysis conducted by the Pew Research Center produced the following table of joint probabilities relat­ing marital status of the three groups defined here.
Marital Status Millenial Generation X Baby Boomer
Single, never married 0.195 0.058 0.030
Married 0.089 0.223 0.201
Living with partner, not married 0.030 0.025 0.009
Divorced, separated, widowed 0.017 0.054 0.070

a. Find the probability that a Millennial is married.
b. Compute the probability that a Baby Boomer is single, never married.
c. Suppose that one person is selected at ran­dom. What is the probability that he or she is married?
d. What is the probability that someone who is living with a partner, but not married is a Generation X?

See attachment for a more legible layout.

Mathematics
1 answer:
nadya68 [22]2 years ago
7 0

Answer:

<u>A. The probability that a Millennial is married is 0.089 or 8.9%.</u>

<u>B. The probability that a Baby Boomer is single, never married is 0.03 or 3%.</u>

<u>C. The probability that one person selected randomly (female or male) is married is 0.513 or 51.3% </u>

<u>D. The probability that someone who is living with a partner, but not married is a Generation X is 0.025 or 2.5%.</u>

Step-by-step explanation:

According to the information provided on the analysis table, we can answer the questions:

A. The probability that a Millennial is married is 0.089 or 8.9%.

B. The probability that a Baby Boomer is single, never married is 0.03 or 3%.

C. The probability that one person selected randomly (female or male) is married is 0.513 or 51.3% (Millennial 0.089 + Generation X 0.223 + Baby boomer 0.201)

D. The probability that someone who is living with a partner, but not married is a Generation X is 0.025 or 2.5%.

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<u>Solution: </u>

Need to calculate value of b so that given system of equations have an infinite number of solutions

\begin{array}{l}{y=6 x+b} \\\\ {-3 x+\frac{1}{2} y=-3}\end{array}

Let us bring the equations in same form for sake of simplicity in comparison

\begin{array}{l}{y=6 x+b} \\\\ {\Rightarrow-6 x+y-b=0 \Rightarrow (1)} \\\\ {\Rightarrow-3 x+\frac{1}{2} y=-3} \\\\ {\Rightarrow -6 x+y=-6} \\\\ {\Rightarrow -6 x+y+6=0 \Rightarrow(2)}\end{array}

Now we have two equations  

\begin{array}{l}{-6 x+y-b=0\Rightarrow(1)} \\\\ {-6 x+y+6=0\Rightarrow(2)}\end{array}

Let us first see what is requirement for system of equations have an infinite number of solutions

If  a_{1} x+b_{1} y+c_{1}=0 and a_{2} x+b_{2} y+c_{2}=0 are two equation  

\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}} then the given system of equation has no infinitely many solutions.

In our case,

\begin{array}{l}{a_{1}=-6, \mathrm{b}_{1}=1 \text { and } c_{1}=-\mathrm{b}} \\\\ {a_{2}=-6, \mathrm{b}_{2}=1 \text { and } c_{2}=6} \\\\ {\frac{a_{1}}{a_{2}}=\frac{-6}{-6}=1} \\\\ {\frac{b_{1}}{b_{2}}=\frac{1}{1}=1} \\\\ {\frac{c_{1}}{c_{2}}=\frac{-b}{6}}\end{array}

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Hence b must be equal to -6 for infinitely many solutions for system of equations y = 6x + b and  -3 x+\frac{1}{2} y=-3

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