Y1 is the simplest parabola. Its vertex is at (0,0) and it passes thru (2,4). This is enough info to conclude that y1 = x^2.
y4, the lower red graph, is a bit more of a challenge. We can easily identify its vertex, which is (-4,0), and several points on the grah, such as (2,-3).
Let's try this: assume that the general equation for a parabola is
y-k = a(x-h)^2, where (h,k) is the vertex. Subst. the known values,
-3-(-4) = a(2-0)^2. Then 1 = a(2)^2, or 1 = 4a, or a = 1/4.
The equation of parabola y4 is y+4 = (1/4)x^2
Or you could elim. the fraction and write the eqn as 4y+16=x^2, or
4y = x^2-16, or y = (1/4)x - 4. Take your pick! Hope this helps you find "a" for the other parabolas.
Answer:
Step-by-step explanation:
The greatest common factor they share is 4.

The answer is going to be 250
Not positively sure but I believe it goes like this
Answer: 9x+26+5x=180
14x+26=180
180-26=14x
14x=154
X=15
Answer:
x=1
Step-by-step explanation:
-2x + 4 = 5 - 3x
Add 3x to each side
-2x+3x + 4 = 5 - 3x+3x
x +4 =5
Subtract 4 from each side
x+4-4 =5-4
x =1